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3 years ago

Pls help thx!!!!!!!!!

Mathematics

2 answers:

Ad libitum [116K]3 years ago

6 0

Answer:

x = 20

Step-by-step explanation:

the two angels are congruet meaning they have the same angle

to find x you plug the two equations equal to each other and solve for x

3x + 50 = 6x - 10

subtract 3x by both sides --> 50 = 3x - 10

add 10 to boths sides --> 60 = 3x

now to get x alone divide boyh sides by 3 --> 60/3 = x

x = 20

Scilla [17]3 years ago

3 0

Answer:

Step-by-step explanation:

$(3x + 50) \degree = (6x - 10) \degree .. (vertical \:\angle s) \\ 3x + 50 = 6x - 10 \\ 3x - 6x = - 10 - 50 \\ - 3x = - 60 \\ x = \frac{ - 60}{ - 3} \\ \huge \red{x = 20}$

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timurjin [86]

If the unknown value is x, then x = $\frac{14}{4}$ × 6 = 21.

Explanation:

Since it is a double number line with a ratio, all the ratios of one number line to the other will remain equal for all the values along both the number lines. Assume the unknown value to be x.
The ratio of the number on the first number line to the corresponding number on the second number line is calculated to be; $\frac{7}{2}$ = $\frac{14}{4}$ = $\frac{x}{6}$ = $\frac{28}{8}$ = $\frac{35}{10}$ = 3.5. So $\frac{x}{6}$ = 3.5, x = 3.5 × 6 = 21.
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3 years ago

Read 2 more answers

Kamal and Anand each Lent the same sum of money for 2 years at 5 percent at simple interest and compound interest respectively.

Ivenika [448]

Answer:

amount lent: ₹6000
interest received: Kamal, ₹600; Anand, ₹615.

Step-by-step explanation:

For principal P invested at simple interest rate r, the returned value in t years is ...

A = P(1 +rt)

If K is Kamal's returned value, the given numbers tell us ...

K = P(1 +0.05·2) = 1.1P

For principal P invested at compound interest rate r, with interest compounded annually for t years, the returned value is ...

A = P(1 +r)^t

If A is Anand's returned value, the given numbers tell us ...

A = P(1.05)² = 1.1025P

This latter amount is RS.15 more than the former one, so we have ...

1.1025P = 1.1P +15

0.0025P = 15 . . . . . . . . subtract 1.1P

P = 6000 . . . . . . . . . . . divide by 0.0025 . . . . the amount lent

Kamal received 1.1P -P = 0.1P = 600 on the investment.

Each lent ₹6000. Kamal received ₹600 in interest; Anand received ₹615 in interest.

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