1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yarga [219]
3 years ago
10

Jonathan’s class has 30 boys. Of the students in his class, 60% are girls. How many girls are in Jonathan’s class?

Mathematics
1 answer:
raketka [301]3 years ago
5 0

Answer:

45 girls

Step-by-step explanation:

  • Remark
  • There are only 2 choices for gender. So if the class is 60% girls, the there must be 100 - 60 = 40% for the boys.
  • But we are told that the boys are 30 in number.
  • Let x = the total number of students.

Solution

  • 40/100 * x = 30              Change the % to a decimal
  • 0.4 x = 30                       Divide both sides by 0.4
  • 0.4 x / 0.4 = 30 / 0.4      Do the division
  • x = 30/0.4
  • x = 75 students in total

Formula

Total of Boys and Girls = Number of boys + number of girls.

Givens

  • Total = 75
  • Number of boys = 30

Solution II

  • 75 = x + 30                 Subtract 30 from each side
  • 75 - 30 = x +30 - 30
  • 45 = x
  • There are 45 girls in the class.
You might be interested in
A new surgical procedure is said to be successful 60% of the time. Suppose the operation is performed five times and the results
USPshnik [31]

Answer:

0.07776, 0.3456,0.08704

Step-by-step explanation:

Given that a new surgical procedure is said to be successful 60% of the time

Let X be the no of successes

Then X has only two outcomes and each trial is independent of the other

Hence X is binomial with p = prob of success in a single trial = 0.60

n = Number of operations performed = 5

Prob that

a) all five operations are successful =

P(X=5)\\= (0.6)^5\\=0.07776

(b) exactly three are successful

=P(X=3) = 5C3 (0.6)^3(0.4)^2\\= 0.3456

(c) less than two are successful

==P(X

3 0
2 years ago
Help me out please :)
NeTakaya
Set it equal to each other. 3x-38+7x-95=47. 10x-133=47. 10x=180. X=18
8 0
3 years ago
The measure of two complementary angles are in the ratio 1:4. What are the degree measures of the two angles ?
777dan777 [17]

Answer:

18,72

Step-by-step explanation:

Complementary angles add to 90 degrees

Multiply the ratio by x

1x+4x = 90

Combine like terms

5x = 90

divide by 5

5x/5 = 90/5

x =18

The first angle is 18 degrees

4*18 =72

The second angle is 72 degrees

7 0
3 years ago
A dime is 1 of a dollar.
Alexxandr [17]

Answer:

A. 10 dimes

B. 30 dimes

Step-by-step explanation:

One dime is ten cents so 10 dimes are 100 witch equals 10

So if 10 dimes is one dollor 30 would be three dollars

8 0
3 years ago
Read 2 more answers
What is the determinant of H<br><br>asap ​
dalvyx [7]

Answer:

H = 15

Step-by-step explanation:

If you need an explnation, I can provide it if needed! Cheers!

3 0
2 years ago
Other questions:
  • What’s the answer when I estimate 110
    6·1 answer
  • A snail travels 9 inches in a span of 3 hours. Which of the following represents the rate of change the snail traveled with resp
    5·2 answers
  • What’s an equivalent expression to 4(4a+5)
    7·1 answer
  • Solve for the missing side length<br><br> Need help please
    6·2 answers
  • I need help asapppppp
    12·2 answers
  • A spinner contains four sections: red, blue, green, and yellow. Joaquin spins the spinner twice. The set of outcomes is given as
    12·2 answers
  • Marie has 11 coins, all of which are quarters and nickels. In all, they're worth $1.15. How many of each kind of coin does Marie
    5·1 answer
  • the population of planet is approximately 280,000 in 2006. Plano is growing 7% per year. What is the population inn 2010? YOUR A
    13·1 answer
  • The Russian ruble coin has a radius of 10.25 mm. What is the circumference in terms of Pi?
    15·2 answers
  • Find the value of x in the given figure​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!