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fiasKO [112]
3 years ago
13

I don’t know how to solve it please help

Mathematics
1 answer:
balandron [24]3 years ago
7 0

Answer:

when x=0 then f(x) = -2

when x=1 then f(x) = 3

when x=2 then f(x) = 8

Step-by-step explanation:

you just plug in the x value given to you into the equation (which is 5x-2) so for example:

if x = 0 then:

5x-2 is instead 5(0)-2 which means you multiply 5 and 0 and then substract 2 because you have to follow PEMDAS

PEMDAS is (Parenthesis, Exponents, Multiplication, Division, Addition, Substraction) which is the order of priority to be solved, so you first solve parenthesis, then exponents, then you multiply or divide, and then you add or substract

easy way to remember PEMDAS: Please Excuse My Dear Aunt Sally, OR Please End My Depression And Suffering (my favorite way to remember, don't take that seriously tho >_>)

so because you have to multiply before subtracting you multiply 5 and 0, you get 0, and then you take away 2 which is -2

remember to just plug in your values and then do PEMDAS

hope you learned something :P

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The answer:
The width is 7cm
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3 years ago
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A moving van changes a flat rate of $25 per day plus $0.12 per mile for every mile over 100 driven.If Millie’s bill was $29.46 h
Damm [24]

Answer: 137.17 miles

Step-by-step explanation: To know the driven miles, we will have to find the extra money paid divided by the unitary price of each driven mile.

Extra money=$29.46-$25=$4.46

Miles=\frac{4.46}{0.12}=31.17 miles

However, this price per mile is only charged after 100 miles, therefore we will have to sum the extra miles driven and the 100 miles for the basis

Total=100 miles+31.17 miles=137.17

5 0
4 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

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1 year ago
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barxatty [35]

Answer:

7,700

Step-by-step explanation:

-175 x 6 = -1,050

-1,050 + 8,750 = 7,700

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3 years ago
Type the correct answer in the box. Use numerals instead of words.
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Answer:

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Step-by-step explanation:

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