we know the segment QP is an angle bisector, namely it divides ∡SQR into two equal angles, thus ∡1 = ∡2, and ∡SQR = ∡1 + ∡2.
A small plane is 20 miles due north of the airport. A jet at the same altitude as the plane is 64.5 miles west of the airport.To
the nearest tenth, what is the distance between the small plane and the jet?Enter your answer as a decimal in the box.
1 answer:
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