Answer:
AAS(Angle-Angle-Side) postulate states that if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then the two triangles are congruent
In triangle RAS and triangle QAT
[Angle]
[Side] [Given]
By Base Angle Theorem states that in an isosceles triangle(i.e, AST), the angles opposite the congruent sides(AS =AT) are congruent.
⇒ 
[By base ∠'s of isosceles triangle are equal]
By definition of supplementary angles, if two Angles are Supplementary when they add up to 180 degrees.
, 
are supplementary and 
, 
are supplementary.
⇒
and
Two 
supplementary to equal
Since, 
then, we get;
[Angle]
then, by AAS postulates,
By CPCT[Corresponding Part of Congruent Triangles are equal]
Hence Proved!
Answer:
centre = (4,-2)
radius = 3
Step-by-step explanation:
The centre-radius form of the circle equation is in the format
(x – h)² + (y – k)² = r²,
with the centre being at the point (h, k) and the radius being "r"
Given in the question an expression which can be write as
<h3> (x – 4)² + (y – (-2))² = 3²</h3>
So, by translating we can say that
centre = (4,-2)
and
radius = 3
Descending order...largest to smallest
the largest one is the one with the biggest exponent
so the first term is : 7z^4
Answer:
Step-by-step explanation:
x²+y²=r²
r²=12
r=√12=2√3
