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2 years ago

a company produces 3 tons of cereal each week how many 12 ounces cereal boxes csn be filled in a week

Mathematics

1 answer:

SVEN [57.7K]2 years ago

6 0

8000.hope this help if not tell me please.

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Resuelve estas ecuaciones<br> 1. x I 6 = 14<br> X=

valentinak56 [21]

Answer:

3 sjshgegegegehsksksjsjsissjs

5 0

2 years ago

Can someone help me with this one ?

Shalnov [3]

Step-by-step explanation:

Using pythagoras theorem

9^2 - 6^2 = x^2

Therefore X^2 = 81 - 36

= 45

Thus X = √45

X = 6.71

5 0

3 years ago

Find the discriminant of the equation. x2 + 3x - 4 = 0

ivann1987 [24]

Please use " ^ " to indicate exponentiation: x^2 + 3x - 4 = 0

Here, a = 1, b = 3 and c = -4.

The formula for the discriminant is b^2 - 4(a)(c).

Substituting the given values of a, b and c, we get:

(3)^2 - 4(1)(-4)

Evaluating this, we get 9 + 16 = 25.

The discriminant is 25.

-3 plus or minus √25

Taking this further, x = ------------------------------------

-3 plus or minus 5

or: x = -------------------------------- => {-4, 1} (solutions)

5 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B

riadik2000 [5.3K]

Let

$S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n$

where we assume |r| < 1. Multiplying on both sides by r gives

$r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}$

and subtracting this from $S_n$ gives

$(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}$

As n → ∞, the exponential term will converge to 0, and the partial sums $S_n$ will converge to

$\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}$

Now, we're given

$a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a$

$a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}$

We must have |r| < 1 since both sums converge, so

$\dfrac{15}a = \dfrac1{1-r}$

$\dfrac{150}{a^2} = \dfrac1{1-r^2}$

Solving for r by substitution, we have

$\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)$

$\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}$

Recalling the difference of squares identity, we have

$\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}$

We've already confirmed r ≠ 1, so we can simplify this to

$\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15$

It follows that

$\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12$

and so the sum we want is

$ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}$

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0

2 years ago

What is the volume of a cylinder with height 4 and radius 2? Use 3.14 for pi.

Over [174]

Answer:

50.27

v=3.14 (2 squared) 4

5 0

3 years ago