3 years ago

Please help me out with this

Mathematics

2 answers:

neonofarm [45]3 years ago

8 0

Answer:

I believe the answer is 12.57

Step-by-step explanation:

9966 [12]3 years ago

8 0

I’m pretty sure it’s 12.57

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A factory produce bicycles at a rate of 110+0.5t^2-0.9t bicycles per week (t in weeks)

klasskru [66]

Answer:

221

Step-by-step explanation:

Day 8 is the first day of the second week.

Day 21 is the last day of week 3.

We need to know the n umber of bicycles made from t = 1 to t = 3

The function is b(t) = 110 + 0.5t^2 - 0.9t, where t is in weeks.

We need to integrate the function with the limits of 1 to 3.

$\int_{1}^{3} (110 + 0.5t^2 - 0.9t) dt$

$\int_{1}^{3} (110 + \dfrac{t^2}{2} - \dfrac{9t}{10}) dt$

$= 110t + \dfrac{t^3}{6} - \dfrac{9t^2}{20} \Biggr|_{1}^{3}$

$= 330.45 - 109.72$

$= 220.7333$

Answer: 221

3 0

3 years ago

Find the amount of interest payable if $400 is borrowed at 14% interest and is to be repaid in 6 months

Shtirlitz [24]

Answer:

The amount of interest payable after 6 months is $28.

Step-by-step explanation:

Here, the Principal amount borrowed = $400

Rate of Interest = 14%

Time = 6 months = 6 / 12 years = 0.5 year

Now, SIMPLE INTEREST = $\frac{P \times R \times T}{100}$

So, here SI = $SI = \frac{400 \times 14 \times 0.5}{100} = 28$

or, SI = $28

Hence, the amount of interest payable after 6 months is $28.

4 0

3 years ago

HELP ASAP 10 POINTS

Elodia [21]

Answer:

596.223

Step-by-step explanation:

3 0

3 years ago

Hello guys can you help me with this

salantis [7]

Answer:

Step-by-step explanation:

7 0

3 years ago

Plz answer fast and correctly,u will be marked brainliest

Sidana [21]

Answer:

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3 years ago

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