Answer:
Acitivy B should be crashed first by 2 days and Activity B has a crash cost per days of $25, it will be crashed for a total of $50.
Explanation:
activity A =
normal time (NT) = 5 days
Normal cost (NC) = $0
crash time (CT) = 3 days
Crash cost (CC) = $500
crash cost per day = [CC - NC]/[CT - NT] = $250/day
activity B:
normal time (NT) = 6 days
Normal cost (NC) = $0
crash time (CT) = 4 days
Crash cost (CC) = $50
crash cost per day = [CC - NC]/[CT - NT] = $25/day
activity C:
normal time (NT) = 8 days
Normal cost (NC) = $0
crash time (CT) = 3 days
Crash cost (CC) = $1000
crash cost per day = [CC - NC]/[ CT- NT] = $200/day
The activity that takes the least cost to speed up is the first one to be crashed. from the computations, activity B takes the least cost to speed up, so the project manager should crash activity B first by 2 days.
Therefore, Acitivy B should be crashed first by 2 days and Activity B has a crash cost per days of $25, it will be crashed for a total of $50.