Question

3-2i/5+i + i " alt="3 - 2i \div 5 + i " align="absmiddle" class="latex-formula">

Answer 1

$3-2i/5+i$

$\frac{3*5+(-2)*1)+(-2*5-3*1)i}{5^2+1^2}$

$\frac{13-13i}{26}=\frac{1-i}{2}$

$=\frac{1}{2}-\frac{1}{2}i$

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