Let the point_1 = p₁ = (1,4)
and point_2 = p₂ = (-2,1)
and Point_3 = p₃ = (x,y)
The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)
The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d =
d₁ =
d₂ =
d₁ = d₂
∴

⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
(x-1)²+(y-4)² = 18
from equatoin (1) y-4 = 1-x
∴(x-1)²+(1-x)² = 18 ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 =

∴ x = 4 or x = -2
∴ y = 1 or y = 7
Point_3 = (4,1) or (-2,7)
Answer:
see explanation
Step-by-step explanation:
(1)
Calculate the circumference (C) of the wheel
C = πd (d is the diameter )
= 3.14 × 8 = 25.12 cm
Now divide the distance travelled by the circumference.
times rotated = 12560 ÷ 25.12 ≈ 500
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(2)
The area (A) of a circle is calculated as
A = πr² ( r is the radius )
Find r by using the circumference (C)
2πr = 50.24 ( divide both sides by 2π )
r = 50.24 ÷ 6.28 = 8 , then
A = 3.14 × 8² = 3.14 × 64 ≈ 200.96 ft² ( student 3 )
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(3)
C = πd = 3.14 × 30 = 94.2 ≈ 94 m
The new size of cube's side is 6. V new cube = 6*6*6 = 216
He would be 25 inches tall.
40 divided by 8 would equal 5 so at age 1, he was 5 inches tall. So 5 times 5 which is how old he was, would equal 25 inches.
Answer:
three u's and an I
Step-by-step explanation:
3×3=9
that's 3 u's so if you add an I its 10