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Sedaia [141]
3 years ago
6

When StartFraction 2 x squared Over y EndFraction = StartFraction w + 2 Over 4 EndFraction is solved for w, one equation is w =

StartFraction 8 x squared Over y EndFraction minus 2 Which of the following is an equivalent equation to find w?
Mathematics
1 answer:
Stells [14]3 years ago
8 0

Answer:

a

Step-by-step explanation:

taking the unit test rn lol

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Find the product of 8*2/3
Nata [24]

Answer:

The Product of 8*2/3

= 16/3

= 5.33

Step-by-step explanation:

7 0
4 years ago
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A 12-foot ladder is placed four feet from the base of a wall.
nikitadnepr [17]

Answer:8sqrt 2 or sqrt 128

Step-by-step explanation:

We can use the Pythagorean Theorem. Since the ladder is leaning against the wall, it is the hypotenuse. It is also 4 feet away from the wall so 12^2-4^2=b^2 b^2=128 so b=8sqrt 2 or sqrt 128.

4 0
3 years ago
Which line is perpendicular to a line that has a slope of -1/3?
Sliva [168]

Answer:

Option (c)

Step-by-step explanation:

Slope of a line that passing through two points M(-1, 4) and N(2, -5),

m_1 = \frac{y_2-y_1}{x_2-x_1}

   = \frac{-1-2}{4+5}

   = -(\frac{3}{9})

   = -\frac{1}{3}

To find the line perpendicular line to MN we will use the property,

m_1\times m_2=-1

Where m_1 and m_2 are the slopes of two perpendicular lines.

Slope of line perpendicular to MN (m_2) will be,

-\frac{1}{3}\times m_2=-1

m_2=3

Slope of line joining two points J(-3, -4) and K(3, -2),

Slope = \frac{-4+2}{-3-3}=\frac{1}{3}

Slope of line joining two points A(-3, 2) and B(3, 0)

Slope = \frac{2-0}{-3-3}=-\frac{1}{3}

Slope of the line joining points E(0, -3) and F(2, 3),

Slope = \frac{-3-3}{0-2} = 3

Therefore, line EF is perpendicular to the line MN.

Option (c) is the answer.

8 0
3 years ago
Anthony wants to find the value of k for which given points W(0,-2), I(2,0) and L(5,k) are collinear
Bogdan [553]

Given:

The three points are W(0,-2), I(2,0) and L(5,k).

To find:

The value of k for which the given points are collinear.

Solution:

We know that, three points are collinear if the area of the triangle formed by these three points is 0.

\dfrac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|=0

x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)=0

The three points are W(0,-2), I(2,0) and L(5,k). So,

0(0-k)+2(k-(-2))+5(-2-0)=0

0+2(k+2)+5(-2)=0

2k+4-10=0

2k-6=0

Adding 6 on both sides, we get

2k=6

k=\dfrac{6}{2}

k=3

Therefore, the correct option is E.

5 0
3 years ago
Write an ordered pair to represent the reflection of the point (4,-1) in the x axis
defon

Answer:

(4,1)

Step-by-step explanation:

The rule for reflecting over the X axis is to switch the value of the y-coordinate of each point, but leave the x-value the same

8 0
3 years ago
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