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pogonyaev
3 years ago
7

Please can anyone solve 9n-10=4n+10

Mathematics
2 answers:
olasank [31]3 years ago
6 0
Yes

remember you can do anything to an equaiton as long as you do it to boh sides
ad try to get unknown to one side
9n-10=4n+10
minus 4n both sides
9n-4n-10=4n-4n+10
5n-10=0+10
add 10
5n+10-10=0+10+10
5n+0=20
5n=20
divide both sies by 5
5n/5=20/5
5/5n=4
1n=4
n=4
sveticcg [70]3 years ago
4 0
9n-10=4n+10
+10           +10
9n=4n+20
-4n     -4n
5n =20
/5     /5
n=4
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28 miles per hour

Step-by-step explanation:

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8) A pyramid has a rectangluar base with length 12 km and width of 5 km. If the volume is 200
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Hi there!

\large\boxed{h = 10km}

We know that the equation for the volume of a pyramid is:

V = 1/3(bh)

We know that:

V = 200 km³

b = 12 × 5 = 60 km²

We can plug these into the equation:

200 = 1/3(60)(h)

Simplify:

200 = 20h

Divide both sides by 20:

200/20 = 20h/20

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2 years ago
What is [70+(-30)]+[2+(-9)]+[0.3+(-0.1)]
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Here is my answer. Hope this help.

8 0
3 years ago
17. What is the area of the figure below?
Sidana [21]

If length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5 cm^{2}.

Given that length of rectangle is 8 cm, Breadth of rectangle is 4 cm,side of square is 3 cm,base of right angled triangle is 3 cm,height of triangle is 5 cm.

Area of figure=Area of rectangle+Area of square+Area of triangle

Area of rectangle=length*breadth

Area of square=Side*Side

Area of triangle=1/2 *Base*Height

Area of figure=8*4+3*3+1/2 *3*5

=32+9+1/2 *15

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Hence if length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5 cm^{2}.

Learn more about area at brainly.com/question/25292087

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