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3 years ago

What number gives a result of −8 when 11 is subtracted from the quotient of the number and 6?

1 answer:

4 0

It is thirteen because you have to add to 6 till you get eleven and you go up 8 more and then you subtract it all and get your answer

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A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

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3 years ago

What is 9×3 +1000×200-50?

valentina_108 [34]

Step-by-step explanation:

The answer to ur question is 199977

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Line p and line q are ______

tino4ka555 [31]

Line p and q are not parallel, because the two given alternate interior angles are not congruent. (It’s B)

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Write an<br> equation of the circle with center (-4,5) and radius 8.

Verizon [17]

Answer:

(x+4)2+(y-5)2=8

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3 years ago

A car travels at a constant speed of 40 mph on the highway.

Alexus [3.1K]

Answer:no

Step-by-step explanation:the trafic may slow down or stop

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3 years ago