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alexandr1967 [171]
4 years ago
9

A mass M is attached to an ideal massless spring. When the system is set in motion, it oscillates with a frequency f. What is th

e new oscillation frequency if the mass is doubled to 2M? g
Physics
1 answer:
jarptica [38.1K]4 years ago
5 0

Answer:

\frac {f_i}{\sqrt 2}

Explanation:

Frequency is given by \frac {1}{2\pi}\sqrt{{\frac {k}{m}}

Let the initial frequency be denoted by f_i

f_i=\frac {1}{2\pi}\sqrt{{\frac {k}{M}}

When M is 2M then

f_f=\frac {1}{2\pi}\sqrt{{\frac {k}{2M}}=\frac {f_i}{\sqrt 2}

Therefore, the final frequency is

\frac {f_i}{\sqrt 2}

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