Alright, it went 1 to the right and down 2 times.
So for point B, you calculate the opposite.
Point B goes 1 left while going up by 2.
(9 - 1, 3 + 2) = (8, 5)
Pre-image point A is (8, 5)
Answer:
7.878 ft far
Step-by-step explanation:
Given:
- A ramp is to be lifted to an angle Q = 10 degrees
- The total length of the ramp L = 8 ft
Find:
- how far does the ramp need to be away to hit the edge of the step
Solution:
- The question asks in "other words" the horizontal distance (d) from the ramp pivot on the floor to the edge of the step when it is lifted 10 degrees.
- We will use trigonometry to solve a right angle triangle: The horizontal distance is a projection of Length L on to the flat ground surface. Hence, we have:
cos(Q) = d / L
d = L*cos(Q)
- Plug in values:
d = 8*cos(10)
Answer: d = 7.878 ft
<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
Rational ! the number doesn't repeat forever or anything like that. it simplifies nicely.