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Lubov Fominskaja [6]
3 years ago
13

Please tell me the answer

Mathematics
1 answer:
Tresset [83]3 years ago
4 0
So it is how many times does 10 go into 40 which is 4 then you do 4 x 3 which is 12 so the answer to the first one is 12/40 and the second one is 42/77. hope this helped
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Marcos bought 3 bags of chips that cost $0.79.
viktelen [127]

Answer:

$2.63

Step-by-step explanation:

3 x $0.79 = 2.37

5.00 - 2.37 = $2.63

8 0
3 years ago
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ABCD is a parallelogram. E is the point where the diagonals AC and BD meet. Prove that triangle ABE is congruent to triangle CDE
Darina [25.2K]
ABCD is a parallelogram                  Given
AE=CE, BE=DE                                <span>The diagonals of a parallelogram are                                                                     bisect each other
</span>∠AEB=∠CED                                    Vertical angles are congruent
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5 0
3 years ago
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AB has one endpoint located at A(-2,
Maru [420]
The other endpoint would be (4,1)
8 0
3 years ago
The function f(x) = x^2 - 2x + 8 is transformed such that g(x) = f(x-2). Find the vertex of g(x).
Serjik [45]

Answer:

Step-by-step explanation:

Since g(x) is f(x-2), every time there is a "x" in the f(x) equation, substitute "x-2". So g(x) would be (x-2)^2-2(x-2)+8. Use the method of trial and error: substitute x as 1,-1, and 3, until you found the right vertex. The answer is B (3,7).

7 0
3 years ago
You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,
Kitty [74]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3

The coordinates of the fourth vertex is D(4,-3)

3 0
4 years ago
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