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deff fn [24]
2 years ago
14

Suppose we want to choose 5 objects, without replacement, from 9 distinct objects. (a) How many ways can this be done, if the or

der of the choices is not taken into consideration? (b) How many ways can this be done, if the order of the choices is taken into consideration?
Mathematics
1 answer:
7nadin3 [17]2 years ago
3 0

Answer:

a. 126

b. 15120

Step-by-step explanation:

5 chose 9 = 9 * 8 * 7 * 6 * 5/1/2/3/4/5 = 126

if order matters...

9*8*7*6*5 = 15120

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Let (12,-5) be a point on the terminal side of an angle 0. Find the values of sin e, cose, and tan
lord [1]

Answer:

Sin = -5/13

Cos = 12/13

Tan = -5/12

Step-by-step explanation:

5 0
3 years ago
A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at
valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

Total = 5 + 6 + 9

Total = 20

This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

4 0
3 years ago
What is the probability of rolling a number greater than 3 on a single die (dice)?
SpyIntel [72]
The probability would be 1/2
8 0
3 years ago
Factor each expression.<br><br> (9) 5a - 25<br><br> (10) 28 - 7x<br><br> (11) 12z + 28 - 7z - 3
Nimfa-mama [501]

Answer:

Step-by-step explanation:

Look for the GCF and then divide every term by the GCF to see what remains

(9) 5a - 25  ( GCF is 5 so take out 5 and divide every term by 5)

     5(a-5)

(10) 28 - 7x     ( GCF is 7 so take out 7 and divide every term by 7)

     7(4-x)

(11) 12z + 28 - 7z - 3=  (combine terms) =

       5x+25( GCF is 5 so take out 5 and divide every term by 5)

        5(x+5)

6 0
2 years ago
Solve this equation x-3=4
MAXImum [283]

Answer:

x-3= 4

x= 4+3

Answer: x= 7

5 0
3 years ago
Read 2 more answers
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