Needing help with this!

Mathematics

1 answer:

Sonbull [250]3 years ago

6 0

assuming the scale is by 1,

a) the slope is rise/run so it rises 3 units and moves 4 units right therefore the slope is 3/4

b) the y intercept is where the line crosses the y axis so by looking at the graph you can tell that the y int is 1

c) and the equation is made up of the slope and the y intercept: y= 3/4x + 1

You might be interested in

Help me solve this problem please

lilavasa [31]

Her mother did not gave her enough money.
each pound of bananas costs 80 cents. 5 pounds of that is $0.8 x 5 = $4.00
each pound of apples costs $1.40. 5 pounds of that is $1.40 x 5 = $7.00
$4.00 + $7.00 = $11.00
Therefore, she needs 11 dollars to buy 5 pounds of each bananas and apples. She needs to ask her mother for 1 more dollar.

5 0

3 years ago

Select the correct answer. Consider the function represented by this graph. Which word or phrase describes the value of the func

goldenfox [79]

Answer:

six and 8

Step-by-step explanation:

6 0

2 years ago

The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in

Anon25 [30]

We have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is $[2,\infty)$ .

If we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

Let us know find its inverse.

$y=(x-5)^{2}+2$

Upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

Let us now solve this function for y.

$(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\$

Hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .