Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
even if the first answer is wrong? Just kidding, the first one is -9, second is 0, third is 9, and last is 18
Step-by-step explanation:
-9
0
9
18
Answer:
It has none. Angle A is obtuse, so it would have to be opposite the longest side. If side a is opposite angle A, then that is not the case.
Step-by-step explanation:
Exact Form: 21/25
Decimal Form: 0.84
Step-by-step explanation: Reduce the expression, if possible, by cancelling the common factors.
Answer:35.2
Step-by-step explanation:
You have to subtract everything to see what it gives you and what it gives u is $35.2
