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vivado [14]
4 years ago
11

Can sometime tell me why the discriminate b^2-4ac doesn't identify trinomial 3x^2+4x-15 as something that's factorable with two

answers? I keep getting a negative number using the discriminate.
Mathematics
1 answer:
Romashka [77]4 years ago
6 0

Answer: Discriminant = 196

<u>Step-by-step explanation:</u>

y = 3x² + 4x - 15

   a=3    b=4   c=-15

Discriminant = b² - 4ac

                     =(4)² - 4(3)(-15)

                     = 16 - (-180)

                     = 16 + 180

                     = 196

If b² - 4ac > 0, then there are 2 real roots/solutions/x-intercepts

If b² - 4ac = 0, then there is 1 real root/solution/x-intercept

If b² - 4ac < 0, then there are 0 real roots/solutions/x-intercepts

                                                (2 imaginary roots/solutions)

Since 196 is positive, there are 2 real roots ....

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Consider the numberless roulette game at a casino. On a spin of the wheel, the ball lands in a space with color red (r), green (
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Answer:

a. Probability of Event A = 2.724037476607E−24

b. G19 = 0.123

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Step-by-step explanation:

Given

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Black (b) = 2

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This is calculated as follows;

Let P(R) = Probability of Red

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Let P(B) = Probability of Black

P(B) = 2/40

Total number of arrangement = 40!/(19!19!2!) = 27,569,305,764,000

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c. Given that you randomly choose to bet red and green only, what is the probability p that you bet a winner?

Let P(R) = Probability of Betting Red

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Let P(Winning) = Probability of Winning

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P(Winning) = ½ * 19/40 + ½ * 19/40

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