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4 years ago

12

What is the volume of a block of ice measuring 3 meters long, 1.5 meters wide, and 2 meters high?

2 answers:

EleoNora [17]4 years ago

8 0

Answer: C
Working Out: 3 x 1.5 x 2 = 9

Licemer1 [7]4 years ago

8 0

The volume (V) of the rectangular prism is the product obtained when we multiply its height (H), length (L), and width (W). Mathematically,
V = H x L x W
Substituting the known values,
V = 2 m x 3 m x 1.5 m =9 m
Thus, the answer is letter C.

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A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation $A=45e^{-0.05t}$ .

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate $A=15$ and solve for t as:

$15=45e^{-0.05t}$

$\frac{15}{45}=\frac{45e^{-0.05t}}{45}$

$\frac{1}{3}=e^{-0.05t}$

Now we will switch sides:

$e^{-0.05t}=\frac{1}{3}$

Let us take natural log on both sides of equation.

$\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})$

Using natural log property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})$

$-0.05t\cdot (1)=\text{ln}(\frac{1}{3})$

$-0.05t=\text{ln}(\frac{1}{3})$

$t=\frac{\text{ln}(\frac{1}{3})}{-0.05}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}$

$t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}$

$t=-\text{ln}(\frac{1}{3})\cdot 20$

$t=-(\text{ln}(1)-\text{ln}(3))\cdot 20$

$t=-(0-\text{ln}(3))\cdot 20$

$t=20\text{ln}(3)$

Therefore, it will take $20\text{ln}(3)$ years for area of the glacier to decrease to 15 square kilo-meters.

6 0

3 years ago

Simplify rational equations <br><br><br><br> y=x^2+3x/x<br><br>Show work, please

lora16 [44]

Answer:

6

Step-by-step explanation:

2y x 3x

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4 years ago

DeSean is sorting his toy car collection. ⅔ of the cars are sports cars. ¼ of the remaining toys are pick up trucks. All of the

user100 [1]

Answer:

Fraction of fire trucks = $\frac{1}{4}$

Total number of toy cars = $16$

Step-by-step explanation:

Fraction of sports car = $\frac{2}{3}$

Fraction of remaining cars $=1-\frac{2}{3}=\frac{3-2}{3} =\frac{1}{3}$

So,

Fraction of pick up cars = $\frac{1}{4}(\frac{1}{3})=\frac{1}{12}$

Therefore,

Fraction of fire trucks = $\frac{1}{3}-\frac{1}{12}=\frac{4-1}{12}=\frac{3}{12}=\frac{1}{4}$

That is Number of fire trucks = $\frac{1}{4}$ ( Total number of toy cars )

Number of fire trucks = 4

Total number of toy cars = $4(4)=16$

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3 years ago

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BigorU [14]

Answer:

7

Step-by-step explanation:

Just multiply all numbers together.

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3 years ago

Write a fraction whose numerator and denominator add up to 9

aalyn [17]

Answer:

5/4

Step-by-step explanation:

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3 years ago