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Naily [24]
2 years ago
8

A point (x, y) is the solution for the inequality y ≥ 2x + 1.

Mathematics
1 answer:
Radda [10]2 years ago
7 0

Answer:

(0,1)

Step-by-step explanation:

We are given that a point (x,y) is the solution for the inequality

y\geq 2x+1

We have to find ordered pair for which y has  a value that is less than or equal to and satisfies the inequality shown.

a.(3,8)

Substitute x=3 and y=8

8\geq 2(3)+1=7

y has a value that is not less than or equal to 1.

b.(1,1)

Substitute x=1

y\geq 2(1)+1=3

But given y=1 which is not greater than or equal to 3.

Therefore,y has a value that is not less than or equal to 1.

c.(2,3)

Substitute x=2

y\geq 2(2)+1=5

3 is not greater than or equal to 5.

It is false.

d.(0,1)

Substitute x=0

y2(0)+1=1

y has a value which is equal to 1.

Hence, (0,1) is true option.

Answer:(0,1)

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2 years ago
3.The following are real data from Santa Clara County, CA. As of a
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  • I) the probability that the person is female is 8.33%.
  • II) the probability that the person has a risk factor heterosexual contact is 6.40%.
  • III) the probability that the person is female or has a risk factor of IV drug user is 23.47%.
  • IV) the probability that the person is female and has a risk factor of homosexual is 0%.
  • V) the probability that the person is male and has a risk factor of IV drug user is 15.13%.
  • VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.

Given the data mentioned in the table, the following calculations must be performed to obtain the requested probabilities:

I.-

(0 + 70 + 136 + 49) / (2,146 + 463 + 60 + 135 + 0 + 70 + 136 + 49) = X

255/3059 = X

0.0833 = X

II.-

196/3059 = X

0.0640 = X

III.-

(255 + 463) / 3059 = X

718/3059 = X

0.2347 = X

IV.-

0/3059 = X

0 = X

V.-

463/3059 = X

0.1513 = X

VI.-

136/196 = X

0.6938 = X

Therefore, I) the probability that the person is female is 8.33%, II) the probability that the person has a risk factor heterosexual contact is 6.40%, III) the probability that the person is female or has a risk factor of IV drug user is 23.47%, IV) the probability that the person is female and has a risk factor of homosexual is 0%, V) the probability that the person is male and has a risk factor of IV drug user is 15.13%, and VI) the probability that the person is female given that the person got the disease from heterosexual contact is 69.38%.

Learn more about maths in brainly.com/question/25815188

3 0
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