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finlep [7]
3 years ago
11

A rectangular pool is 20 feet wide and 50 feet long. A deck used for sunning surrounds the pool. The deck is the same width all

the way around the pool. The total area of the deck is 456 square feet. How wide is the walkway?
A. 2 feet
B. 3 feet
C. 4 feet
D. 5 feet
Mathematics
2 answers:
Darya [45]3 years ago
8 0
The answer is b. 3 ft
GalinKa [24]3 years ago
7 0
Ahh, this question goes all the way back to my year 9 test a couple years ago; which I got wrong back then - I now know how

Firstly we find the expression for the area (using x as the walk way):
>50x * 2 (the left and right) 
>20x * 2 (the top and bottom)
>4 * x^2 (the corners)

Add them all together , Area = 140x + 4x^2
Now we place the deck's area, <u>456</u> into the expression

456 = 140x + 4x^2

Solve for x
I'm a bit rusty on this i'm afraid, but I believe the only way to solve this is to factorise it
0 = 4x^2 + 140x - 456
0 = 4(x+38)(x-3)            <
<u>x must = -38 or = +3 (the numbers inside the brackets inverted)</u>
x must = +3 as it's logical, you can't have a negative width


The walkway is 3 feet wide, we can put this into our expression to double check this,
<em>456 = 140*(3) + 4(3)^2</em>
<em>456 = 420 + 4*9</em>
<em>456 = 420 + 36</em>
<em>456 = 456
</em>Yes, 3 feet wide is correct.


*Note, 
I tried to keep this simple, please let me know if I didn't go into enough detail anywhere
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3 0
3 years ago
the interest on an investment varies directly as the rate of of interest. if interest is $47 when interst rate is 5% find the in
NNADVOKAT [17]

Answer:

The interest when rate is 5.2% is $48.88

Step-by-step explanation:

if interest (I) varies directly as interest rate (R)

Then

I ∝ R

I=cR

c= constant

if interest is $47 when interest rate is 5%

47 =.05c

c = 940

if interest rate is 5.2% then

I = 940 x .052

=48.88

=$48.88

7 0
3 years ago
Find the area of the composite figure.
Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

  • Since Length = 6 in ;

\longrightarrow \rm \: 6 \: in   = radius

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

  • Total Horizontal Distance= 14
  • Radius = 6

\longrightarrow\rm \: Breadth = 14-6

\longrightarrow\rm \: Breadth = 8 \: in

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

  • Length = 6
  • Breadth = 8

\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

\longrightarrow \rm \: Area \:  of  \: Rectangle = 48 \: in {}^{2}

Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

  • r = radius = 6
  • π = 3.14

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

  • \rm Area_{(rectangle)} = 48
  • \rm Area_{(Quarter Circle)} = 28.26

\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

3 0
1 year ago
A new episode of Charlie's favorite TV series will be aired 25 minutes after Charlie gets home from school. Which method should
Tresset [83]

Answer:

Charlie should use a stopwatch with minutes and seconds

Step-by-step explanation:

charlie should not count in his head as it is not accurate, he could count too fast or slow

Charlie should not look at that clock and the seconds will affect the 25 minutes, whether it be less or more

Charlie should not use an hourglass as he might flip it over too soon or quick and it's not very accurate

therefore using the stopwatch allows him to accurately and fairly keep track of the exact time

4 0
2 years ago
Please help!!!!!!!!!!!!!!!!!!!!
Valentin [98]

Answer:

I am not sure but think that the answer is 1/20

7 0
2 years ago
Read 2 more answers
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