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Natasha_Volkova [10]
2 years ago
15

*Quadratic equations*solve(i) (x+3)(x-4)=0(ii) (2x-3)(x-1) =0​

Mathematics
1 answer:
Ivanshal [37]2 years ago
3 0

Answer:

(i) (x+3)(x-4)=0

  • x+3= 0 ⇒ x= -3
  • x-4= 0⇒ x= 4

(ii) (2x-3)(x-1) =0​

  • 2x-3= 0 ⇒ 2x=3 ⇒ x= 3/2
  • x- 1= 0 ⇒ x= 1
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Since the right parts of the equation are equal, therefore the left parts of the equation are also equal:

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