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Natasha_Volkova [10]
2 years ago
15

*Quadratic equations*solve(i) (x+3)(x-4)=0(ii) (2x-3)(x-1) =0​

Mathematics
1 answer:
Ivanshal [37]2 years ago
3 0

Answer:

(i) (x+3)(x-4)=0

  • x+3= 0 ⇒ x= -3
  • x-4= 0⇒ x= 4

(ii) (2x-3)(x-1) =0​

  • 2x-3= 0 ⇒ 2x=3 ⇒ x= 3/2
  • x- 1= 0 ⇒ x= 1
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Answer:

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General Formulas and Concepts:
<u>Algebra I</u>

Equality Properties

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Let's solve for the <em>general</em> equation that allows us to find the hypotenuse:

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Now that we have the <em>formula</em> to solve for the hypotenuse, let's figure out what <em>x</em> is equal to:

  1. [Equation] <em>Substitute</em> in variables:
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∴ the hypotenuse length <em>x</em> is equal to √909 and the number <em>under</em> the square root, our answer, is equal to 909.

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Learn more about Trigonometry: brainly.com/question/27707750

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Topic: Trigonometry

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