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2 years ago

Quadratic equationssolve(i) (x+3)(x-4)=0(ii) (2x-3)(x-1) =0

Mathematics

1 answer:

Ivanshal [37]2 years ago

3 0

Answer:

(i) (x+3)(x-4)=0

x+3= 0 ⇒ x= -3
x-4= 0⇒ x= 4

(ii) (2x-3)(x-1) =0

2x-3= 0 ⇒ 2x=3 ⇒ x= 3/2
x- 1= 0 ⇒ x= 1

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Step-by-step explanation:

Given,

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Let,

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Multiplying Eqn 1 by 50

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Dividing both sides by 5

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Keywords: linear equation, elimination method

Learn more about elimination method at:

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3 years ago

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Answer:

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Read 2 more answers

*Quadratic equations*solve(i) (x+3)(x-4)=0(ii) (2x-3)(x-1) =0​

Quadratic equationssolve(i) (x+3)(x-4)=0(ii) (2x-3)(x-1) =0