*Quadratic equations*solve(i) (x+3)(x-4)=0(ii) (2x-3)(x-1) =0
1 answer:
Answer:
(i) (x+3)(x-4)=0
- x+3= 0 ⇒ x= -3
- x-4= 0⇒ x= 4
(ii) (2x-3)(x-1) =0
- 2x-3= 0 ⇒ 2x=3 ⇒ x= 3/2
- x- 1= 0 ⇒ x= 1
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