3 years ago

C equals 5/9 F32 the nearest whole degree what is the temperature in the degrees Fahrenheit when it is 90 degrees Celsius

1 answer:

5 0

$C=\dfrac{5}{9}(F-32)\\\\C=90\to 90=\dfrac{5}{9}(F-32)\ \ \ |\cdot\dfrac{9}{5}\\\\F-32=162\ \ \ |+32\\\\F=194\\\\\boxed{90^oC=194^oF\to D}$

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