Question

C equals 5/9 F32 the nearest whole degree what is the temperature in the degrees Fahrenheit when it is 90 degrees Celsius

Answer 1

$C=\dfrac{5}{9}(F-32)\\\\C=90\to 90=\dfrac{5}{9}(F-32)\ \ \ |\cdot\dfrac{9}{5}\\\\F-32=162\ \ \ |+32\\\\F=194\\\\\boxed{90^oC=194^oF\to D}$