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tekilochka [14]
3 years ago
8

What is 12 divided by 6/7

Mathematics
2 answers:
Naddik [55]3 years ago
8 0
What is the easiest way to divide whole numbers to fractions?
Just follow these two easy steps:
1. Multiply the whole number  to the denominator of the fraction. In other words, the bottom number of the fraction will be multiplied to the whole number, like this:

12 ÷ 6/7 = n
 <u>   6    </u>
7 x 12
You will have 6/ 84.
2. Simplify.
6  = 1, 2, 3, 6
84= 1, 2, 3, 4, 6, 7, 12, 14, 21, 42, 84

the GCF is 6.  divide both numbers by 6, so the answer will be 1/14.

You can also get the reciprocal and proceed to multiplication , like this: (12/1 is the fractional form or the whole number 12.)
 1/12 x 6/7=n
that makes 6/84 or 1/14.
Sever21 [200]3 years ago
6 0
12 / (6/7) = x
x = 12 * 7/6
x = 14

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The diagram shows an empty cylindrical container. Ana puts a solid cube of side length 8 cm into the container. She then pours 1
marshall27 [118]

Answer:

<h3><u>Cylinder</u></h3>

\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

Given:

  • r = 6 cm
  • h = 18 cm

\begin{aligned}\implies \sf V &= \sf \pi (6)^2(18)\\& = \sf 648 \pi \: cm^3\end{aligned}

<h3><u>Cube</u></h3>

\textsf{Volume of a cube}=\sf x^3\quad\textsf{(where x is the side length)}

Given:

  • x = 8 cm

\begin{aligned}\implies \sf V &= 8^3\\& = \sf 512 \: cm^3\end{aligned}

<h3><u>Volume available to be filled with water</u></h3>

Volume of cylinder - volume of cube

= 684π - 512

= 1532.75204 cm³

    1 litre = 1000 cm³

⇒ 1.5 litres = 1000 × 1.5 = 1500 cm³

As 1500 < 1532.75204, the volume of water poured into the container is smaller than the empty space available in the cylinder.  Therefore, the water will <u>not</u> come over the top of the container.

4 0
2 years ago
Find the area :<br> (see question in picture)
quester [9]

I cant really see the full question

4 0
2 years ago
What's the missing sequence of 37 40 123 ? 372 1116 <br>​
erica [24]

Answer:

369

Step-by-step explanation:

37 + 3 = 40

40 × 3 = 120

120 + 3 = 123

123 × 3 = 369

and so on

6 0
3 years ago
In adjoining figure a circle is inscribed in the quadrilateral ABCD given that BC is equal to 38 cm cube is equal to 27 cm and B
lukranit [14]

<h3>Radius = 14cm</h3>

Step-by-step explanation:

Let O be the centre of the circle. Since P and S are the points of contact of tangents AD and DC respectively, OP ⊥ AD and OS ⊥ DC

Also, AD ⊥ DC (given), therefore, OPDS is a square.

BR = BQ = 27cm...(tangents from an external point to a circle are equal in length)

therefore, CR = CB - BR = (38 - 27)cm = 11cm

SC = CR = 11 cm...(tangents from an external point) therefore, DS = DC - SC = (25 - 11) cm = 14 cm.

therefore,

Radius of a circle = OP = DS = 14 cm...(therefore, OPDS is a square).

<h3>Hope it helps you!! </h3>
5 0
2 years ago
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