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3 years ago

What is 12 divided by 6/7

2 answers:

8 0

What is the easiest way to divide whole numbers to fractions?
Just follow these two easy steps:
1. Multiply the whole number to the denominator of the fraction. In other words, the bottom number of the fraction will be multiplied to the whole number, like this:

12 ÷ 6/7 = n
<u> 6 </u>
7 x 12
You will have 6/ 84.
2. Simplify.
6 = 1, 2, 3, 6
84= 1, 2, 3, 4, 6, 7, 12, 14, 21, 42, 84

the GCF is 6. divide both numbers by 6, so the answer will be 1/14.

You can also get the reciprocal and proceed to multiplication , like this: (12/1 is the fractional form or the whole number 12.)
1/12 x 6/7=n
that makes 6/84 or 1/14.

Sever21 [200]3 years ago

6 0

12 / (6/7) = x
x = 12 * 7/6
x = 14

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If travel at a rate of 45 mph how many minutes will it take you to travel 1 mile

xz_007 [3.2K]

Every minute you would travel .75 miles, but divide that by 3 and you get 1 minute and 33 seconds.

4 0

3 years ago

A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0

2 years ago

Helppppppppppppooppppoopp

Lyrx [107]

Answer:

Let x rep the lenght of the shorter one

Then the longer one is 2x+1

Therefore

(2x+1) + x = 16

We now solve for x

2x + 1 + x = 16

Group and evaluate like terms

3x +1 = 16

3x = 16 -1

× = 15/3

x = 5

So the shorter one is 5 ft

The longer one is 2(5)+1= 11

4 0

3 years ago

How many Solutions does this system have? (1 point)

mixas84 [53]

The given system of equation that is $2x+y=3$ and $6x=9-3y$ has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

$\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}$

Let us first bring the equation in standard form for comparison

$\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}$

$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

To check how many solutions are there for system of equations $a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0$ , we need to compare ratios of $\frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}$

In our case,

$a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3$

$a_{2} = 6, b_{2} = 3,\text{ and }c_{2} = -9$

$\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}$