Answer:
20
Step-by-step explanation:
Givens
Let child one = x
Let child two = y
Let child three = z
Equations
x^2 + y^2 + z^2 = 100
xy + xz + yz = 150
Solution
There's a trick here. The square of their weights added together is equal (with some modification) to the given conditions. Start by squaring (x+y+z).
(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2xz + 2yz
Take out 2 as a common factor from the last three terms.
(x + y + z)^2 = (x^2 + y^2 + z^2+ 2(xy + xz + yz) )
Substitute the given conditions into the equation. (x^2 + y^2 + z^2) = 100 and 2*(xy + xz + yz) = 2 * 150
(x + y + z)^2 = 100 + 2*150
(x + y + z)^2 = 100 + 300
(x + y + z)^2 = 400
Take the square root of both sides.
sqrt(x+y+z)^2 = sqrt(400)
x + y + z = 20
Note
This answer tells you nothing about the values of x y and z. On the other hand it does not ask for the values of x y and z.
Answer:
Step-by-step explanation:
=
Answer:
Step-by-step explanation:
4b + 8 = 20
Subtract 8 from both sides
4b + 8 - 8 = 20 - 8
4b = 12
Now divide both sides by 4
4b/4 = 12/4
b = 3
Check:
LHS = 4b + 8
= 4*3 + 8
= 12 + 8
= 20 = RHS
60= 35_x then 1.732= 35_5 then x= 20.21 then 1.732_1.732 = 35_1.732 hope this helps :D
