Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
3^6 power. it would be 3 to the 6th power
A because the week would be equal to the 3 books he read
Answer:
Step-by-step explanation:
5.70 divided by 3
witch would be $1.90
Decimal: Divide 16 by 25: 0.64
Percent: move the decimal 2 places to the left: 64, then add a percent sign: 64%
