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kozerog [31]
3 years ago
12

If the vertex of a parabola is (2,-9) and another point on the curve is (5,18), what is the coefficient of the squared expressio

n in the parabola’s equation?
Helppp!!! will mark Brainliest
Mathematics
1 answer:
Trava [24]3 years ago
6 0

Hi! I just wanted to let you know if you go to the site gizmos, it is an amazing site to help with parabolas and graphing, another place to visit is algebra nation select Algebra 1 though, you can talk 1 on 1 with a math professional!

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Richard was thinking of a number. Richard adds 9.5 to the number, then doubles the result to get an answer of 59.4. Form an equa
Jet001 [13]
The answer is 49.9 because he thought of a number and added 9.5 and the result was 59.4 then you should do 59.4-9.5 and the answer is 49.9
7 0
3 years ago
Read 2 more answers
Continuation of the other six questions find the value of eggs and tangent 
n200080 [17]

Answer:

Step-by-step explanation:

1) ?

I can't see what that one given angle is ..  but it's that  mystery angle subtracted from 180 give the angle   BOA   then you know that's an isosceles triangle again that the BOA is part of... so then just subtract BOA from 180 to find the two other angle of that triangle... they are the small so just divide your answer of  180-BOA /2 is the angle of each.. then since you know those to smaller angles subtract one from 90  to find the angle BAX

2) ( as we would read normally)

You're making this really tough on me.. I can just barely read the equations

I think it's  1+6x  and 7x-3  .  b/c they are the same length sides you can set those equal

1+6x = 7x -3

4+6x = 7x

4 = x

that worked out well :

for the tangent..   it's   Tan(Ф)= Opp/ Adj

but I don't know which side they want to solve for.. I think you may have left off some of the instructions????  :/

ohh I think they really mean.. what's the length of the tangent lines .. that was confusing to me.. :/ just plug in 4 into x for either eq.

1+6(4) = 25

or

7(4)-3=25

tangent is 25

3)

x-2 = 2x-10

x+8 = 2x

8 = x

again they made it work out easy :)

Then plug 8 into either equation to find the length of the tangent lines

8-2=10

tangent is 10

4) = 2)   ??? they are the same question  maybe  you meant to put something else?

5 0
3 years ago
For each value of y, determine whether it is a solution to -2y+75-5.<br> Is it a solution?
ser-zykov [4K]

Answer:

• No

• Yes

• Yes

• No

Step-by-step explanation:

To determine if the 4 given values of y are solutions to the inequality, start by solving the inequality. Solving an inequality is just like that of an equation, except that the direction of the sign changes when the inequality is divided by a negative number.

-2y +7≤ -5

Subtract 7 on both sides:

-2y≤ -5 -7

-2y≤ -12

Divide by -2 on both sides:

y≥ 6

This means that the solution can be 6 or greater than 6.

-10 and 3 are smaller than 6 and are not a solutions, while 7 and 6 satisfies the inequality and are therefore solutions.

_______

Alternatively, we can also substitute each value of y into the inequality and check if the value is less than or equal to -5.

Here's an example to check if -10 is a solution.

-2y +7≤ -5

When y= -10,

-2y +7

= -2(-10) +7

= 20 +7

= 27

Since 27 is greater than 5, it is <u>not</u> a solution to the inequality.

3 0
2 years ago
A line passes through the point (-2, 3) and has a slope of -2. What is the equation of the line?
Mrrafil [7]

Answer:

y = -2x -1

Step-by-step explanation:

slope intercept form is y = mx +b

m = slope, b = y intercept

point is given as ordered pair (x,y)

plug in slope into y=......

y= -2x+b

plug in the point

3 = -2 * (-2) + b

3= 4 +b subtract 4 on each side

b = -1

y = -2x -1

8 0
3 years ago
Ignore circled one and work it out please​
mash [69]

Answer:

a. \frac{(x-7)}{x^2+x-30}

Step-by-step explanation:

\huge \frac{x^2-3x-28}{(x^2+10x+24)(x-5)} \\\\\huge {=\frac{x^2-7x+4x-28}{(x^2+6x+4x+24)(x-5)}}\\\\\huge {=\frac{x(x-7)+4(x-7)}{\{x(x+6)+4(x+6)\}(x-5)}}\\\\\huge {=\frac{(x-7)(x+4)}{(x+6)(x+4)(x-5)}}\\\\\huge {=\frac{(x-7)}{(x+6)(x-5)}}\\\\\huge {=\frac{(x-7)}{x^2+(6-5)x+6(-5)}}\\\\\huge {=\frac{(x-7)}{x^2+x-30}}

3 0
3 years ago
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