just separate the ramge and domain
The answer is 5-3/2x. Hope this helps :)
The area enclosed is (2x)(600-2x).(2x)(600−2x)=1200x−4x2
In order to maximize we need the derivative to be equal to 0.y′=1200−8x=0
1200=8x
x=150
Therefore the sides for maximum area are 150*300.
<span>The area is: 45000</span>
Answer:
Step-by-step explanation:
Approximate the integral 
by dividing the region 
with vertices (0,0),(4,0),(4,2) and (0,2) into eight equal squares.
Find the sum 
Since all are equal squares, so 
for every 
Thus, 
Evaluating the iterate integral ![\int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=\int\limits^4_0 {[xy+\frac{y^2}{2} ]}\limits^2_0 \, dx =\int\limits^4_0 {[2x+2]}dx\\\\=[x^2+2x]\limits^4_0=24.](https://tex.z-dn.net/?f=%5Cint%5Climits%5E4_0%20%5Cint%5Climits%5E2_0%20%7B%28x%2By%29%7D%20%5C%2C%20dydx%3D%5Cint%5Climits%5E4_0%20%7B%5Bxy%2B%5Cfrac%7By%5E2%7D%7B2%7D%20%5D%7D%5Climits%5E2_0%20%5C%2C%20dx%20%3D%5Cint%5Climits%5E4_0%20%7B%5B2x%2B2%5D%7Ddx%5C%5C%5C%5C%3D%5Bx%5E2%2B2x%5D%5Climits%5E4_0%3D24.)
Thus, 
Since you did not specify the place value, I am assuming that it is the ones place.
Since half of a hundred is 50, and you round up when its half or higher, the greatest whole number would be 49.
Final answer: 67449
