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densk [106]
3 years ago
9

A bike rental company charges a $5 service fee and $1 per hour. If this situation is represented as a function, what would be th

e slope?
Mathematics
2 answers:
Svet_ta [14]3 years ago
5 0

Answer:

setback grizzly drizzle

Step-by-step explanation:

st

Elenna [48]3 years ago
4 0
Write as a function equation: where f(x) is the same as "y"

f(x) = 5 + 1x   ------  y = 1x + 5

Use:  y = mx + b  (Where m = slope and b is y intercept)

Slope is 1 and y intercept is +5 

Remember slope is rise over run so 1 can be written as 1 / 1 and interpreted as rise 1 and run 1 both in the positive direction. 



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Which would NOT be an appropriate way to generate 10 random integers to use in one trial of a probability simulation?
Vlada [557]
A. Make a list of the first 10 integers that come to your head should NOT be used
6 0
3 years ago
Read 2 more answers
PLEASE HELP! The LCM of 10 and 12 is ___.
slava [35]

Answer:

<em>LCM</em><em> </em><em>of</em><em> </em><em>12</em><em> </em><em>and</em><em> </em><em>10</em><em>=</em><em> </em><em>60</em>

<em>hope</em><em> </em><em>this helps</em><em> </em><em><</em><em>3</em>

5 0
3 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
3 years ago
Write the equation of a line passing through (6,-2) and perpendicular to -2x + 3y= -6
____ [38]
Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.


-2x+3y=-6                 Add 2x in both sides
3y=2x-6                    Divide by 3 in both sides to isolate y
y=2/3x-6/3


The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.

y=mx+b                 Substitute the given point and the previous slope found
-2=(-3/2)(6)+b       Combine like terms
-2=-9+b                 Add 9 in both sides to isolate b
7=b

The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.


4 0
3 years ago
Please explain or show how you got the answer
natka813 [3]
The answer is D) $0.15

James spent: $2.65
On 5 box of markers and 1 erase
So I divided 2.65 by 5 and got .15
$2.65 ÷ 5 = 0.15
So he spent $2.50 on markers an $0.15
Erasers

Based of James, Becky spent a dollar on. 2 boxes of markers
And $0.45 on 3 erasers

Hope I helped if so mark me as brainliest
3 0
3 years ago
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