Nate solve the equation 3 times 5 equals 15 by writing and solving 15 divided by 5 is 3 x plane why Nate's method works

How to do this and I need help pls

tatuchka [14]

Answer:

$9$

Step-by-step explanation:

$f(x) = (x - 2)^{2} \\ f(5) = (5 - 2)^{2} \\ f(5) = {(3)}^{2} \\ f(5) = 3 \times 3 \\ f(5) = 9$

7 0

3 years ago

The wall street journal corporate perceptions study 2011 surveyed readers and asked how each rated the quality of management and

malfutka [58]

Answer:

Hello some parts of your question is missing below is the missing part

answer : A) p-value = 0.0019 ,

The level of significance ( 0.05 ) > p-value ( 0.0019 )

B) There is no dependence between the two ratings

Step-by-step explanation:

A) using a 0.05 level of significance and test for independence of the quality of management

Test statistic : $X^{2}$ ∑ ( Oi - Ei )^2 / Ei

= [(40-35)^2 / 35 ] + [(25-24.5)^2 / 24.5 ] + [(5-10.5)^2 / 10.5] + [(35-40)^2 / 40] + [(35-28)^2 / 28] + [(10-12)^2 / 12] + [ (25-25)^2 / 25 ] + [(10-17.5)^2 / 17.5 ] + [(15-7.5)^2 / 7.5] = 17.03

p-value = 0.0019

Df = 4 ,

The level of significance ( 0.05 ) > p-value ( 0.0019 )

B) There is no dependence between the two ratings

4 0

2 years ago

For a school play, 739 tickets valued at $857 were sold. Some cost $1 and others cost a $1.50. How many $1 tickets were sold?

balu736 [363]

Answer:

503 $1 tickets sold.

Step-by-step explanation:

Use two equations

Let x = number of $1 tickets sold

Let y = number of $1.50 tickets sold

x + y = 739

1x + (1.5)y = 857

First equation ==> y = 739 - x

Plug this into the second equation

x + (1.5)(739 - x) = 857

x + 1108.5 - 1.5x = 857

- 0.5x = -251.5

x = 503

There were 503 $1 tickets sold.

To find the number of $1.50 tickets, just plug this value of x into either one of the equations.

(503) + y = 739 (739 - 503 = 236)

y = 236

There were 236 $1.50 tickets sold.

3 0

3 years ago

1 point) Use Stoke's Theorem to evaluate ∫CF⋅dr∫CF⋅dr where F(x,y,z)=xi+yj+1(x2+y2)kF(x,y,z)=xi+yj+1(x2+y2)k and CC is the bound

Drupady [299]

Answer:

0

Step-by-step explanation:

Thinking process:

$\int\limits^a_b {cF} \, .dr$

= $\int\limits^a_b {x} \, dx \int\limits^a_b {x} \, dx curlFdS$ by Stoke's Theorem

= $\int\limits^a_b {} \, \int\limits^a_b {} \, < 12y, -12x, 0 > .< z_x,-z_y, 1 > dA\\= \int\limits^a_b {} \, \int\limits^a_b {} \, < 12y, -12x, 0 > .< 2x, 2y, 1 > dA$ since z = $25-x^{2} -y^{2} \\= 0$