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irinina [24]
3 years ago
5

What is the length to the nearest tenth of the altitude of an equilateral triangle with a perimeter of 30 inches

Mathematics
1 answer:
MrRa [10]3 years ago
3 0
Each side of an equilateral triangle = perimeter / 3.
Each side = 10 inches.
The altitude divides the triangle into two 30 60 90 triangles.  The hypotenuse is 10 inches and the short side is 5 inches.
altitude^2 = 10^2 - 5^2
altitude^2 = 100 - 25
altitude^2 = 75
altitude = <span> <span> <span> 8.6602540378 </span> </span> </span>

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Marla bought one necklace and two bracelets for $67.50. Use the following information to determine the amount she paid for each
alexdok [17]
Ooh, scary math

n+2b=67.5
n=27
27+2b=67.5
minus 27 both sides
2b=40.50
divide both sides by 2
b=20.25

a bracelet costs $20.25
8 0
3 years ago
Read 2 more answers
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
Can you please help me with this question and i will give you a Brainiest
Flauer [41]

Answer:

infinite soulutions

Step-by-step explanation:

m+7=3+m+4

m+7=m+3+4 (Combine Like Terms)

m+7=m+7

Step 2: Subtract m from both sides

m+7−m=m+7−m

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4 0
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enyata [817]
2 x 2/9 Will Be Less Than 2
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2 years ago
Can I get some help please? <br><br><br> Thanks!
quester [9]
An ellipse (oval shape) is expressed by the following equation:

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We can find the foci by using a^2 - b^2 = c^2

36 - 11 = c^2

c =  \sqrt{25}  = 5

Since the k value in this case is 0, the y value of both foci are 0. Also, since h and k are both 0, we know the center of the ellipse is at the origin.

So the foci are (-5, 0) and (5, 0)

Hope this helps :)

3 0
3 years ago
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