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irinina [24]
3 years ago
5

What is the length to the nearest tenth of the altitude of an equilateral triangle with a perimeter of 30 inches

Mathematics
1 answer:
MrRa [10]3 years ago
3 0
Each side of an equilateral triangle = perimeter / 3.
Each side = 10 inches.
The altitude divides the triangle into two 30 60 90 triangles.  The hypotenuse is 10 inches and the short side is 5 inches.
altitude^2 = 10^2 - 5^2
altitude^2 = 100 - 25
altitude^2 = 75
altitude = <span> <span> <span> 8.6602540378 </span> </span> </span>

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olga_2 [115]

Answer:

20th: 100 nth: 5

Step-by-step explanation:

the table is multiplying by 5

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8 0
3 years ago
See attachment below
KatRina [158]

Answer: Third Option

x=1.469743

Step-by-step explanation:

We have the following exponential equation

3^{x+1}=15

We must solve the equation for the variable x

To clear the variable x apply the log_3 function on both sides of the equation

log_3(3^{x+1})=log_3(15)

Simplifying we get the following:

x+1=log_3(15)

To simplify the expression log_3 (15) we apply the base change property

log_b(y)=\frac{log(y)}{log(b)}

This means that:

log_3 (15)=\frac{log(15)}{log(3)}

Then:

x+1=\frac{log(15)}{log(3)}

x=\frac{log(15)}{log(3)}-1

x=1.469743

6 0
3 years ago
Hiking up a mountain, you notice that the air temperature drops 10°C for every 1,000 meters increase in elevation. Write a multi
den301095 [7]

Answer:

30,000

Step-by-step explanation:

7 0
3 years ago
A school track is shown the straightaway on each side measures 1,000 meters the curves are semicircles with diameter 74 meters w
lisov135 [29]

Answer:

2232.48 meters

Step-by-step explanation:

From the diagram:

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The length of school track :

Straightway on each side = 2 * 1000 m = 2000m

Length of semicircle = πr/2

Length of both semicircle  = 2 * 3.142 * 74 /2 = 232.47785

Total Length = ( 2000 + 232.47785) = 2232.48 meters

7 0
3 years ago
In △ABC , point D is between points A and B, and point E is between points B and C. Point Y is the incenter of the triangle, YD¯
n200080 [17]

Answer:

Answer: Using the proportions between the segments, the area of the triangles are:

1. Area of triangle ADC is 25 in^2.

2. Area of triangle BDC is 15 in^2.

3. Area of triangle CDE is 12 in^2.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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