Answer:
D) v = -2,000y + 20,000.
Step-by-step explanation:
The question gives a linear relationship between two quantities. This means that the relationship between the initial value of the car and the amount it depreciates each year is proportional, or constant. Since the value of the car decreases by 10% of its initial value each year, then each year the value will decrease by 10% of 20,000 or 0.10 x 20000 = $2,000. Since we know the value is decreasing each year, this amount would be subtracted from the initial value of $20,000. So, D) v = -2,000y + 20,000 would be the only equation that represents this scenario.
<span>The graph you plotted is the graph of f ' (x) and NOT f(x) itself. </span>
Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get
f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24
So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5
<span>f ' (x) = (x-4)(6-2x)
</span><span>f ' (3.5) = (3.5-4)(6-2*3.5)
</span>f ' (3.5) = 0.5
The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.
So the final answer is C) 3
Answer:
23X
Step-by-step explanation:
Answer:
gfhgfhgfujghgdghhtcfhggjufhhggfhg
Step-by-step explanationbfd:
Answer:
A and b
Step-by-step explanation: Because ....
