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Setler79 [48]
4 years ago
9

Solve a, b, c, & d please & I will mark you as Brainliest.

Mathematics
2 answers:
laila [671]4 years ago
8 0

Answer:

Step-by-step explanation:

a) -2x-3y=5\\-5x+3y=-40\\-7x=-35\\x=5, y=-5\\\\b)5x+6y=-14\\x-2y=10\\Considering\ equation\ 2,\\3(x-2y)=3(10)\\3x-6y=30\\Hence,\\5x+6y=-14\\3x-6y=30\\8x=16\\x=2, y=-4\\\\c) -3x+3y=21\\-x-5y=-17\\Considering\ equation\ 2,\\3(-x-5y)=3(-17)\\-3x-15y=-51\\Hence, subtracting\ both\ the\ equations\ we\ get,\\-3x+3y=21\\3x+15y=51\\18y=72\\y=4, x=-3

d) Let the cost of one group lesson be x and one private lesson be y

12x+2y=110\\10x+3y=125\\By\ multiplying\ the\ first\ equation\ with\ -1.5\ in\ this\ system\ we\ get,\\-1.5(12x+2y)=-1.5(110)\\-18x-3y=-165\\Hence,\ by\ adding\ both\ the\ equations\ we\ get,\\-18x-3y=-165\\10x+3y=125\\-8x=-40\\x=5,y=25

erica [24]4 years ago
8 0

A,B,C

Step-by-step explanation:

D, 12x + 2y= 110

10x + 3y= 120

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A circle's radius that has an initial radius of 0 cm is increasing at a constant rate of 5 cm per second.
djyliett [7]

Answer:

a) r(t)=5t

b) A=\pi\cdot r^2

c) A=\pi\cdot (5t)^2

d) A=25\pi  t^2

Step-by-step explanation:

We know that the circle is increasing its radio from an initial state of r=0 cm, at a rate of 5 cm/s.

This can be expressed as:

r(0)=0\\\\dr/dt=5\\\\r(t)=r(0)+dr/dt\cdot t=0+5t\\\\r(t)=5t

a) Radius of the circle, r (in cm), in terms of the number of seconds, t since the circle started growing:

r(t)=5t

b) Area of the circle, A (in square cm), in terms of the circle's radius, r (in cm):

A=\pi\cdot r^2

c) Circle's area, A (in square cm), in terms of the number of seconds, t, since the circle started growing:

A=\pi\cdot r^2\\\\A=\pi\cdot (5t)^2

d) Expanded form for the area A:

A=\pi\cdot (5t)^2=25\pi\cdot t^2

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V125BC [204]
\bold{ANSWER:}
x = 40

\bold{SOLUTION:}

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