Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
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Answer:
Step-by-step explanation:
Given the equation y = 2,5x
y is the height of the water
x is the time.
To get the range of values of the height at t = 60s, we will substitute x = 60 into the function
y = 2.5(60)
y = 150 in
Hence the range of the situation is [0, 150].
The domain will be all positive integers i.e xEZ
I"d say the answer is A im happy to help whenever have a good day!
-3 1/2
just add the fractions
Mark brainliest please
I think the volume is 200
