1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
Answer:
There is nothing there...
Step-by-step explanation:
There is nothing at all.
Answer:
4917
Step-by-step explanation:
<u>Given sequence: </u>
This is AP with common difference of 1, the first term of 42 and the last term of 107
<u>Number of terms:</u>
<u>Sum of the terms:</u>
- Sₙ= 1/2*66*(42+107) = 4917
<u>Answer is:</u> 4917
Answer:
It will cost 11 cents a day.
Step-by-step explanation:
1.98/18=11
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