What are the zeros of this function?
1 answer:
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Always do what's in parentheses first:
Then do multiplication and division:
Then addition and subtraction last:
<h2>Answer:</h2>
(a)
(b)
(c)
We are given a function f(x) as :
(a)
We will substitute (x+h) in place of x in the function f(x) as follows:
(b)
Now on subtracting the f(x+h) obtained in part (a) with the function f(x) we have:
(c)
In this part we will divide the numerator expression which is obtained in part (b) by h to get:
Answer:
[-3, ∞)
Step-by-step explanation:
There are many ways to find the range but I will use the method I find the easiest.
First, find the derivative of the function.
f(x) = x² - 10x + 22
f'(x) = 2x - 10
Once you find the derivative, set the derivative equal to 0.
2x - 10 = 0
Solve for x.
2x = 10
x = 5
Great, you have the x value but we need the y value. To find it, plug the x value of 5 back into the original equation.
f(x) = x² - 10x + 22
f(5) = 5² - 10(5) + 22
= 25 - 50 +22
= -3
Since the function is that of a parabola, the value of x is the vertex and the y values continue going up to ∞.
This means the range is : [-3, ∞)
Another easy way is just graphing the function and then looking at the range. (I attached a graph of the function below).
Hope this helped!
The result of the log function is 60
According to the law of logarithm if then
Given the following expressions
This can be expressed as
Substitute the value of m and n into the expression to have:
This shows that the result of the log function is 60
Learn more here: brainly.com/question/12049968