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Paul [167]
3 years ago
9

ILL BRAINLIEST YOU IF YOU PLEASE HELP ME AND ILL GIVE 30 EXTRA POINTS

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer:

Step-by-step explanation:

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A parabola has a vertex at the origin. The focus of the parabola is located at (–2,0).
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3 years ago
Estimate the sum to the nearest whole number <br><br> 29.1 +78.9 + 41.5
lesya692 [45]

I rounded each number to the nearest whole number and added those.

29 + 79 + 42 = 150

If you add the original numbers you would get 149.5, which rounds to 150.

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3 years ago
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I have problems in solving this questions<br> f(x)=x2+6x+3<br> t (x)= x-3/x+4<br> then find (f.t)(x)
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3 years ago
Find S8 for the geometric series 3 + -6 + 12 + -24 +…
kirill115 [55]
I guess you are asking to find the sum of the first 8 terms. If so, then:
Sum = a₁(1-rⁿ)/(1-r), where a₁ is the 1st term,  r=common ratio and n=number of terms:
the 1st term a₁ =3
common ratio r = - 2 (since -6/3 = - 2, and 12/-6 = - 2, etc.)

Sum = 3[(1- (-2)⁸]/(1-2) = 3(1- 256)/(1/2)
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6 0
3 years ago
a statistics professor finds that when he schedules an office hour at the 10:30a, time slot, an average of three students arrive
Veseljchak [2.6K]

Answer:

The probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.

Step-by-step explanation:

Let <em>X</em> = number of students arriving at the 10:30 AM time slot.

The average number of students arriving at the 10:30 AM time slot is, <em>λ</em> = 3.

A random variable representing the occurrence of events in a fixed interval of time is known as Poisson random variables. For example, the number of customers visiting the bank in an hour or the number of typographical error is a book every 10 pages.

The random variable <em>X</em> is also a Poisson random variable because it represents the fixed number of students arriving at the 10:30 AM time slot.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.

The probability mass function of <em>X</em> is given by:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...,\ \lambda>0

Compute the probability of <em>X</em> = 2 as follows:

P(X=2)=\frac{e^{-3}3^{2}}{2!}=\frac{0.0498\times 9}{2}=0.2241

Thus, the probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.

6 0
3 years ago
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