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natka813 [3]
3 years ago
15

Which of the following statements best explains how the high-gain antenna in Voyager probes has made outer space exploration eas

ier?
A It produces magnetic fields.
B It measures the charged particles of solar winds.
C It sends cosmic rays to the sun and other planets.
D It can send data to Earth.
Computers and Technology
1 answer:
Alina [70]3 years ago
8 0
The answer is (D) It can send data to Earth.

The High-Gain Antenna on the voyagers transmits data back to earth on 2 frequency channels. One channel transmits at about 8.4ghz and is in the X-band channel that contains engineering data. The other channel transmits data at around 2.3ghz and is in the S-band.






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Consider the language S*, where S = {a ab ba}.
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Answer:

Check Explanation

Explanation:

A) the string (abbba) is not a word in this language because in this language, each b must preceded or followed by an a. Three consecutive b's are just not possible.

B) All the words with 3 letters in this language

aaa

aab

aba

baa

C) 5 words with four letters from this language. I'll write as many as possible to make things as easy as possible.

aaaa

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aaba

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D) This is the language of words without bbb, with every bb preceded and followed by an a (that is, no word can start or end wilth bb). All non-empty strings contain at least one a (so b and bb together are not allowed!).

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8_murik_8 [283]

Answer:

#include<iostream>

#include<string>

using namespace std;

class zip_code

{

private:

int zipcode;

string get_string(int num)

{

string str="";

if(num == 0) return "11000";

if(num>7)

{

str.append("1");

num = num-7;

}

else

str.append("0");

if(num>4)

{

str.append("1");

num = num-4;

}

else

str.append("0");

if(num>2)

{

str.append("1");

num = num-2;

}

else

str.append("0");

if(num>1)

{

str.append("1");

num = num-1;

}

else

str.append("0");

str.append("0");

return str;

}

public:

zip_code(int barcode)

{

if(barcode<10000 || barcode>99999)

cout <<"Invalid Bar code passed to constructor." << endl;

else

zipcode = barcode;

}

zip_code(string barcode)

{

if(barcode.length()>27)

cout <<"Invalid Bar code passed to constructor." << endl;

else

{

int zipper = 0;

string str_local = barcode.substr(1,barcode.length()-2);

for(int i=0; i<str_local.length()-5; i+=5)

{

int local = 0;

local = 7*(str_local[i]-'0') +

       4*(str_local[i+1]-'0') +

       2*(str_local[i+2]-'0') +

       1*(str_local[i+3]-'0');

if(local == 11) local = 0;

       zipper = zipper*10 + local;

}

zipcode = zipper;

}

}

string getZipcode()

{

string str = "1";

int first = zipcode/10000;

int second = (zipcode - first*10000)/1000;

int third = (zipcode - first*10000-second*1000)/100;

int fourth = (zipcode - first*10000-second*1000-third*100)/10;

int fifith = (zipcode - first*10000-second*1000-third*100-fourth*10);

str.append(get_string(first));

str.append(get_string(second));

str.append(get_string(third));

str.append(get_string(fourth));

str.append(get_string(fifith));

str.append("1");

return str;

}

int get_zipCode()

{

return zipcode;

}

};

int main()

{

zip_code z1(123456);

zip_code z2(99504);

cout << z2.getZipcode() << endl;

system("pause");

return 0;

}

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