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3 years ago

Show an equation equivalent to 12+18

Mathematics

2 answers:

scZoUnD [109]3 years ago

5 0

10+10+10=30 this might be right but i dont know

attashe74 [19]3 years ago

5 0

16 * 2
16 + 16
10 + 20

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Suppose you were deciding on a ticket price for a fundraiser dinner. There may be a temptation to continue to raise the ticket s

cestrela7 [59]

Answer:

$50 per ticket.

Step-by-step explanation:

Although it is tempting to keep raising the price for a higher profit, if you raise the price by too much, people will stop buying tickets and you will not gain as much money as you could have gotten with, say, $50 per plate.

The more you raise the price, the less tickets you can sell.

Hope this helps!

6 0

3 years ago

Boxes of raisins are labled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is re

kati45 [8]

Answer:

The 99 % confidence interval on the basis of mean is ( 21.7393 ; 22.0257)

Step-by-step explanation:

Mean = Sum of observations / Number of observations

Mean = 21.88 +21.76 +22.14 +21.63+ 21.81 +22.12+ 21.97+ 21.57+ 21.75+ 21.96 +22.20 +21.80/ 12

Mean =x`= 262.59/12= 21.8825

Standard Deviation = s= ∑x²/n - ( ∑x/n)²

∑x²/n= 478.7344 +473.4976 + 490.1796+467.8569+ 475.6761 + 489.2944+ 482.6809+ 465.2649+ 473.0625+ 482.2416 +492.84 + 475.24/ 12

∑x²/n= 5746.5689/12= 478.8807 = 478.881

Standard Deviation = s= ∑x²/n - ( ∑x/n)²

s= 478.881- (21.8825)²= 478.881-478.843= 0.037

The confidence limit 99% for the mean will be determined by

x` ± α(100-1) √s/n

Putting the values in the above equation

= 21.8825 ± 2.58 √0.037/12

Solving the square root

= 21.8825 ± 2.58 (0.05549)

Multiplying the square root with 2.58

=21.8825 ± 0.1432

Adding and subtracting would give

21.7393 ; 22.0257,

Hence the 99 % confidence interval on the basis of mean is ( 21.7393 ; 22.0257)

5 0

3 years ago

Let f(x) ln(1+t^2)dt find f'(x) find the critical numbers of f g

OverLord2011 [107]

X1y hope it helps I'm just starting out

7 0

3 years ago

5 cups to 8 cups MATH HELP!

Nonamiya [84]

Answer:

If it's an addition problem then just add 3 cups

Step-by-step explanation:

There isn't too much context here buddy :p

6 0

3 years ago

What value of k makes the equation true? (5a^2 b^3)(6a^k b)=30a^6 b^4

Ratling [72]

we are given

$(5a^2 b^3)(6a^k b)=30a^6 b^4$

Firstly, we will simplify left side

and then we can solve for k

Left side is

$(5a^2 b^3)(6a^k b)$

we can arrange like terms

$(5a^2 6a^k)(b^3 b)$

$(5\times 6 a^2a^k)(b^3 b)$

$(30 a^2a^k)(b^3 b^1)$

now, we can use property of exponent

$a^m \times a^n=a^{m+n}$

$(30 a^{2+k})(b^{3+1})$

$30a^{2+k}b^{4}$

now, we can equate it with right side

and we get

$30a^{2+k}b^{4}=30a^6 b^4$

We can see that both sides have 30 , a and b

and they are equal

so, exponent of a must also be equal

$2+k=6$

now, we can solve for k

$2+k-2=6-2$

$k=4$ ................Answer

3 0

4 years ago

Read 2 more answers