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amid [387]
3 years ago
11

Suppose you were deciding on a ticket price for a fundraiser dinner. There may be a temptation to continue to raise the ticket s

ales to increase the amount of money raised. Sounds like an okay idea to raise the most money possible for a charity. You may have heard of a guest speaker at a fundraising dinner where people are charged $100 a plate or more. What do you think is a realistic price for tickets? What are the consequences of raising the price $50 or $100 to $150 a plate or $200 a plate.
Mathematics
1 answer:
cestrela7 [59]3 years ago
6 0

Answer:

$50 per ticket.

Step-by-step explanation:

Although it is tempting to keep raising the price for a higher profit, if you raise the price by too much, people will stop buying tickets and you will not gain as much money as you could have gotten with, say, $50 per plate.

The more you raise the price, the less tickets you can sell.

Hope this helps!

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At any given time, the amount of money in a club's bank account will equal the starting amount plus the amount saved each week. We can set up an equation for each club that adds these two parts together to give us that total:

$ saved up by each club after X weeks = starting $ + ($ saved per week)*(X number of weeks)

For each club, here are the equations we need:

Total $ Saved by Science Club after X weeks = 20 + 10X
Total $ Saved by Music Club after X weeks = 50 + 5X
Total $ Saved by Math Club after X weeks = 0 + 15X

We can use "Y" to represent the total $ saved by each club:


Ysci = 20 + 10X

Ymus = 50 + 5X

Ymath = 15X

To find all the possible times when any two clubs will have saved the same amount of money, we just need to graph these three equations and find the points where each pair of lines intersect. After graphing the equations, we're looking for the X-values for the intersection points where:

1) Ysci = Ymus

(The point at which 20 + 10X = 50 + 5X)

2) Ysci = Ymath

(The point at which 20 + 10X = 15X)

Ymus = Ymath

(The point at which 50 + 5X = 15X)


We can check the graphing solution by solving these pairs of equations with algebra. We just combine all "X" terms on one side and all number terms on the other side to solve for X.

1) Ysci = Ymus

20 + 10X = 50 + 5X

5X = 30

X = 6

2) Ysci = Ymath

20 + 10X = 15X

20 = 5X

X = 4

Ymus = Ymath

50 + 5X = 15X

50 = 10X

X = 5

Answer Summary:
1) $ saved by Science Club = $ saved by Music Club after 6 weeks;
2) $ saved by Science Club = $ saved by Math Club after 4 weeks;
3) $ saved by Music Club = $ saved by Math Club after 5 weeks.

7 0
3 years ago
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