3 years ago

a local University wanted 2300 students out of 4500 applications for admission where was the acceptance rate as a percentage

1 answer:

5 0

2300\4500*100=
51.11%

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Annette [7]

The answer to this is -9

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3 years ago

Tom [10]

Step-by-step explanation:

9/8 × (-7/3) =

9 × -7 = -63

8 × 3 = 24

-63/24 simplify

-21/8

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lubasha [3.4K]

186 miles in that time

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LiRa [457]

I think this is right

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3 years ago

gogolik [260]

False

because tan^2 45 = 1^2 = 1
and sec^2 x = 1/ cos^2 45 = (sqrt2)^2 = 2

so the sum = 3

3 0

3 years ago

a local University wanted 2300 students out of 4500 applications for admission where was the acceptance rate as a percentage​