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oksian1 [2.3K]
4 years ago
11

Model a desert community where 60% is houses, 10% is shops, and 30% is parks. The area of the community that is houses is repres

ented by squares. The area of the community that is shops is represented by squares. The area of the community that is parks is represented by squares.
Mathematics
2 answers:
Nina [5.8K]4 years ago
8 0

Answer:

jwjwkzoisudjheaaaaaaakakachenß it itch

zaharov [31]4 years ago
6 0

Answer:

6 of the squares have shops.  

Step-by-step explanation:

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1. The mechanics at Lincoln Automotive are reborning a 6 in deep cylinder to fit a new piston. The machine they are using increa
Firdavs [7]

Answer:

0.0239\frac{in^{3}}{min}

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram of the cylinder. (See attached picture)

This diagram will help us visualize the problem better.

So we start by determining what data we already know:

Height=6in

Diameter=3.8in

Radius = 1.9 in (because the radius is half the length of the diameter)

The problem also states that the radius will increase on thousandth of an inch every 3 minutes. We can find the velocity at which the radius is increasing with this data:

r'=\frac{1/1000in}{3min}

which yields:

r'=\frac{1}{3000}\frac{in}{min}

with this information we can start solving the problem.

First, the problem wants us to know how fast the volume is increasing, so in order to find that we need to start with the volume formula for a cylinder, which is:

V=\pi r^{2}h

where V is the volumen, r is the radius, h is the height and π is a mathematical constant equal approximately to 3.1416.

Now, the height of the cylinder will not change at any time during the reborning, so we can directly substitute the provided height, so we get:

V=\pi r^{2}(6)

or

V=6 \pi r^{2}

We can now take the derivative to this formula so we get:

\frac{dV}{dt}=2(6)\pi r \frac{dr}{dt}

Which simplifies to:

\frac{dV}{dt}=12\pi r \frac{dr}{dt}

We can now substitute the data provided by the problem to get:

\frac{dV}{dt}=12\pi (1.9) (\frac{1}{3000})

which yields:

\frac{dV}{dt}=0.0239\frac{in^{3}}{min}

3 0
4 years ago
The length of a rectangle is a inches. Its width is 5 inches less then the length. Find the area and perimeter of the rectangle
Travka [436]

Answer:

Area = (a² -5a) in²

Perimeter = (4a -10) in

Step-by-step explanation:

Let the length of the rectangle be a.

Given that, its width is 5 in less than the length.

So,

length ⇒ a

width ⇒ (a - 5)

First, let's find the area of the rectangle.

Area = length × width

Area = a ( a - 5 )

<em>Solve the brackets.</em>

Area = <u>(a² -5a) in²</u>

<u />

Now, let us find the perimeter of the rectangle.

Perimeter = 2 ( l + w )

Perimeter = 2 ( a + a - 5 )

Perimeter = 2 ( 2a - 5 )

Perimeter = <u>(4a -10) in</u>

3 0
2 years ago
Use the figure to find the measure of the numbered angles.
dybincka [34]

Answer:

I am not sure how your figure is, but I am using one of mine figure.

<1 is corresponding with <5.

<2 is corresponding with <6.

<3 is corresponding with <7.

<4 is a corresponding angle with the given angle.

<5 and <7 are vertical to the given angle.

<6 is a supplementary to the given angle.

I am not sure if answer is right, but hopw this helps, thank you :) !!

6 0
3 years ago
How do you use common core (mental math) to find the answer to:<br><br> 8×25×23=?
IgorC [24]
Mental math I'd split it up and simplify it first.

8 × 25 is 4 × 25 two times. So 100 times anything is just the number plus two zeros usually so 

8 × 25 × 23
100 × 23 
2300                               2300 Is the answer
5 0
4 years ago
Round 43.786 to the nearest hundredth
serious [3.7K]
43.786

Since 6 rounds up:

43.79

Hope this helps!
3 0
3 years ago
Read 2 more answers
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