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1 year ago

The length of a rectangle is a inches. Its width is 5 inches less then the length. Find the area and perimeter of the rectangle

Mathematics

1 answer:

Travka [436]1 year ago

3 0

Answer:

Area = (a² -5a) in²

Perimeter = (4a -10) in

Step-by-step explanation:

Let the length of the rectangle be a.

Given that, its width is 5 in less than the length.

So,

length ⇒ a

width ⇒ (a - 5)

First, let's find the area of the rectangle.

Area = length × width

Area = a ( a - 5 )

Solve the brackets.

Area = (a² -5a) in²

Now, let us find the perimeter of the rectangle.

Perimeter = 2 ( l + w )

Perimeter = 2 ( a + a - 5 )

Perimeter = 2 ( 2a - 5 )

Perimeter = (4a -10) in

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4) 8(-2 + 2n) + 3n = 40 +5n

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Answer:

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2 years ago

What is the solution to x – 10 > – 12? (–∞, –18) (–18, ∞) (–∞, 18) (18, ∞)

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Answer:

(18, ∞)

Step-by-step explanation:

(18, ∞) is the only option that works. if we ignore the "greater than" sign, and just set the function equal to -12, we see that x-10=-12 would give us x=-2. If we plug in -3 for x, we get -13, which is less than -12. if we plug in -1 for x, we get -11, which is greater than -12. Therefore, with the function only having one critical point (zero), we know that every value greater than -2 is a solution. Technically, the full solution would be (-2, ∞). however, the only answer available meeting the criteria would be (18, ∞).

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3 years ago

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Find the value of x at which the function has a possible relative maximum or minimum point. (Recall that e Superscript x is pos

shutvik [7]

Answer:

x= -11/4 is a maximum.

Step-by-step explanation:

Remember that a function has its critical points where the derivative equal zero. Therefore we need to compute the derivative of this function and find the points where the derivative is zero. Using the chain rule and the product rule we get that

$f'(x)= -e^{-4x}(11+4x)$

And then we get that if $11+4x = 0$ then $x = -11/4$ . So it has a critical point at $x = -11/4$ .

Now, if the second derivative evaluated at that point is less than 0 then the point is a maximum and if is greater than zero the point is a minimum.

Since

$f''(x) = 8e^{-4x} (5+2x)\\f''(-11/4) = -239496.56$

x= -11/4 is a maximum.

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3 years ago