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2 years ago

The length of a rectangle is a inches. Its width is 5 inches less then the length. Find the area and perimeter of the rectangle

Mathematics

1 answer:

Travka [436]2 years ago

3 0

Answer:

Area = (a² -5a) in²

Perimeter = (4a -10) in

Step-by-step explanation:

Let the length of the rectangle be a.

Given that, its width is 5 in less than the length.

So,

length ⇒ a

width ⇒ (a - 5)

First, let's find the area of the rectangle.

Area = length × width

Area = a ( a - 5 )

Solve the brackets.

Area = (a² -5a) in²

Now, let us find the perimeter of the rectangle.

Perimeter = 2 ( l + w )

Perimeter = 2 ( a + a - 5 )

Perimeter = 2 ( 2a - 5 )

Perimeter = (4a -10) in

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Brut [27]

Answer:

Area of Shaded Region $=50\pi$ cm^2$

Area of Semicircle $=50\pi$ cm^2$

$\dfrac{\text{Area of Shaded region}}{\text{Area of Square}}=\dfrac{ \pi}{8}$

Step-by-step explanation:

Area of Shaded Region = Area of Sector - Area of Semicircle

Area of Sector

Radius of the sector =20cm

$=\frac{90}{360}X\pi *20^2\\ =100\pi cm^2$

Area of Semicircle

Since AB is the diameter of the semicircle

Radius of the Semicircle=20/2=10cm

Area of semicircle

$=\frac{\pi r^2}{2}\\ =\frac{\pi *10^2}{2}\\=50\pi cm^2$

Therefore, area of Shaded Region

$=100\pi -50 \pi\\=50\pi$ cm^2$

Area of Square =20 X 20 $=400 cm^2$

$\dfrac{\text{Area of Shaded region}}{\text{Area of Square}} \\=\dfrac{50 \pi}{400} \\=\dfrac{ \pi}{8}$

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Gala2k [10]

Answer:

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Step-by-step explanation:

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3 years ago

Find three consecutive odd integers such that the product of the first and the second exceeds the third by 8

Svetlanka [38]

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Ignore $x=-4$ since it's an even integer.

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