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m_a_m_a [10]
2 years ago
13

The length of a rectangle is a inches. Its width is 5 inches less then the length. Find the area and perimeter of the rectangle

Mathematics
1 answer:
Travka [436]2 years ago
3 0

Answer:

Area = (a² -5a) in²

Perimeter = (4a -10) in

Step-by-step explanation:

Let the length of the rectangle be a.

Given that, its width is 5 in less than the length.

So,

length ⇒ a

width ⇒ (a - 5)

First, let's find the area of the rectangle.

Area = length × width

Area = a ( a - 5 )

<em>Solve the brackets.</em>

Area = <u>(a² -5a) in²</u>

<u />

Now, let us find the perimeter of the rectangle.

Perimeter = 2 ( l + w )

Perimeter = 2 ( a + a - 5 )

Perimeter = 2 ( 2a - 5 )

Perimeter = <u>(4a -10) in</u>

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Answer:

1. n= 14

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Step-by-step explanation:

For the first problem, let's break down the equation. The number being thought about can be represented by <em>n</em>. Then <em>n </em>is increased by 7, or simply put 7+ <em>n. </em>The sum is 21, so to find n you can use the equation 7 + n = 24 and solve for <em>n, </em>which is 14.

For problem two, the same strategy can be used. The number is <em>n, </em>multiplied by 9. So, 9 * <em>n</em> is equal to 27. Solve for n by isolating n, and the answer is 3.

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Answer:

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Sherry had an ending balance f 125.36, outstanding deposits of 153.53, and utstanding checks of $100.19. What was her checkbook
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Answer:

The checkbook balance is $178 .7.

Step-by-step explanation:

As given

Sherry had an ending balance $ 125.36, outstanding deposits of $153.53, and outstanding checks of $100.19.

Thus

Checkbook balance = Ending balance + Outstanding deposits -  Outstanding checks

Putting the values in the above

Checkbook balance = $ 125.36 + $153.53 - $100.19

                                  = $ 278.89 - $100.19

                                  = $ 178.7

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3 years ago
The sum of c and 9 is equal to 16​
amid [387]

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Step-by-step explanation:

The sum means to add c and 9, that is

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5 0
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A bag contain 5 red marbles,4 green marbles and 1 blue marble. A marble is chosen at random from the bag and not replaced; then
jarptica [38.1K]

Answer:

\frac{2}{15}

Step-by-step explanation:

GIVEN: A bag contain 5 red marbles,4 green marbles and 1 blue marble. A marble is chosen at random from the bag and not replaced, then a second marble is chose.

TO FIND: What is the probability both marbles are green.

SOLUTION:

Total marbles in bag =10

total number of green marbles =4

Probability that first marble will be green P(A)=\frac{\text{total green marbles}}{\text{total marbles}}

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Probability that second marble will be green P(B)=\frac{\text{total green marble in bag}}{\text{total marble in bag}}

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As both events are disjoint

probability both marbles are green =P(A)\times P(B)

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Hence  the probability both marbles are green is \frac{2}{15}

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