18% of
238.8889 is 43.
Convert the percentage (18) to a decimal by dividing it over 100:

Divide 43 over 0.18:
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The range that the amount withheld vary if the weekly wages, after subtracting withholding allowances, vary from $600 to $700 inclusive is: 76.35<x<101.35.
<h3>Range</h3>
Given
592<x1317
74.35+.25
Hence:
Lowest range
74.35+.25(600-592)
74.35+.25(8)
74.35+2
=76.35
Highest range
74.35+.25(700-592)
74.35+.25(108)
74.35+27
=101.35
Range
76.35<x<101.35
Therefore the range that the amount withheld vary if the weekly wages, after subtracting withholding allowances, vary from $600 to $700 inclusive is: 76.35<x<101.35.
Learn more about range here: brainly.com/question/2264373
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Answer:
The mean of the distribution of sample means is 27.6
Step-by-step explanation:
We are given the following in the question:
Mean, μ = 27.6
Standard Deviation, σ = 39.4
We are given that the population is a bell shaped distribution that is a normal distribution.
Sample size, n = 173.
We have to find the mean of the distribution of sample means.
Central Limit theorem:
- It states that the distribution of the sample means approximate the normal distribution as the sample size increases.
- The mean of all samples from the same population will be approximately equal to the mean of the population.
Thus, we can write:

Thus, the mean of the distribution of sample means is 27.6