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KATRIN_1 [288]
3 years ago
15

Round 43.786 to the nearest hundredth

Mathematics
2 answers:
serious [3.7K]3 years ago
3 0
43.786

Since 6 rounds up:

43.79

Hope this helps!
Yuliya22 [10]3 years ago
3 0
The hundereths at are on the right side 43.790 next to the ones place value. Witch is before the desimal

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Using the Segment Addition Postulate, find the value of m.
Naya [18.7K]

Answer:

36

Step-by-step explanation:

AB + BC = AC

4m - 15 + 5m - 6 = 15

m - 21 = 15

m = 36

4 0
3 years ago
The target temperature for a laboratory is 72° Fahrenheit. It
myrzilka [38]

The inequality |t - 72| ≤ 2 represents the target temperature for a laboratory is 72° Fahrenheit, and it can vary by up to 2° option (D) is correct.

<h3>What is inequality?</h3>

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than, known as inequality.

The question is incomplete.

The complete question is in the picture, please find the attached picture.

We have:

The target temperature for a laboratory is 72° Fahrenheit. It can vary by up to 2°.

Target temperature = 72 degree Fahrenheit

It can vary by up to 2°. (the highest limit)

The temperature in the laboratory represented by t

Now,

inequality represents this situation is:

|t - 72| ≤ 2

Thus, the inequality |t - 72| ≤ 2 represents the target temperature for a laboratory is 72° Fahrenheit, and it can vary by up to 2° option (D) is correct.

Learn more about the inequality here:

brainly.com/question/19491153

#SPJ1

6 0
2 years ago
Question 1 of 10
sp2606 [1]

20 raise the power 7

Step-by-step explanation:

Which clearly means 20 × itself 7 times

3 0
2 years ago
Assume that the cheetah travels an average of 40 mph to go from its resting place to a rock near a river. On the return trip to
Ronch [10]

Answer:

The return trip take 5 minutes 27 seconds

Step-by-step explanation:

Let

x -----> the time it take the cheetah travels to go from its resting place to a rock near a river in hours

y ----> the time it take the cheetah the return trip to its resting place in hours

we know that

The distance from its resting place to a rock near a river is the same that the return trip

The average speed multiplied by the time is equal to distance

so

The total time is 15 minutes

Convert to hours

15 min=15/60 hours

x+y=(15/60)

x+y=1/4

4x+4y=1 -----> equation A

40x=70y ----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point ( 0.1591,0.0909)

see the attached figure

The time it take the cheetah travels to go from its resting place to a rock near a river is 0.1591 hours

The time it take the cheetah the return trip to its resting place is 0.0909 hours

Convert to minutes and seconds

0.0909 hours=0.0909(60)=5.454 minutes

o.454 minutes=0.454(6)=27.24 seconds

therefore

The return trip take 5 minutes 27 seconds

<u><em>To the river</em></u>

The time it take the cheetah travels to go from its resting place to a rock near a river is 0.1591 hours

The rate is 40 mph

To find out the distance multiply the average rate by the time

<em>Find out the distances</em>

The distance from its resting place to a rock near a river is

d_1=40x=40(0.1591)=6.36\ miles

<u><em>From the river</em></u>

The time it take the cheetah the return trip to its resting place is 0.0909 hours

The rate is 70 mph

To find out the distance multiply the average rate by the time

<em>Find out the distances</em>

The distance of the return trip is

d_2=70x=70(0.0909)=6.36\ miles

Both distances are the same

8 0
3 years ago
What is the following product? (2V7 +3V6)(5V2+4V3)
raketka [301]

(2\sqrt{7}+3\sqrt{6})(5\sqrt{2}+4\sqrt{3}) \\\\\\ \begin{array}{lllllll} 10\sqrt{14}&+&15\sqrt{12}&+&8\sqrt{21}&+&12\sqrt{18}\\\\ &&15\sqrt{2^2\cdot 3}&&&&12\sqrt{3^2\cdot 2}\\\\ &&15\cdot 2\sqrt{3}&&&&12\cdot 3\sqrt{2}\\\\ &&30\sqrt{3}&&&&36\sqrt{2}\\\\ 10\sqrt{14}&+&30\sqrt{3}&+&8\sqrt{21}&+&36\sqrt{2}\\\\ 10\sqrt{14}&+&8\sqrt{21}&+&30\sqrt{3}&+&36\sqrt{2} \end{array}

5 0
2 years ago
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