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sdas [7]
2 years ago
12

How much is 8% of 800 tons?

Mathematics
1 answer:
bonufazy [111]2 years ago
5 0
1. We assume, that the number 800 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 800 is 100%, so we can write it down as 800=100%.
4. We know, that x is 8% of the output value, so we can write it down as x=8%.
5. Now we have two simple equations:
1) 800=100%
2) x=8%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
800/x=100%/8%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 8% of 800

800/x=100/8
(800/x)*x=(100/8)*x - we multiply both sides of the equation by x
800=12.5*x - we divide both sides of the equation by (12.5) to get x
800/12.5=x
64=x
x=64

now we have:
8% of 800 tons =64 Tons
I hope this helped!!
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Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

               M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let (x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⇒ d=\sqrt{(2-5)^2+(4-3)^2}

⇒d=\sqrt{9+1}

⇒d=\sqrt{10}   ....(1)

Now, we find the length of M'K'

let (x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)

d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}

⇒ d^{'}=\sqrt{(-2+5)^2+(3-4)^2}

⇒d^{'}=\sqrt{9+1}

⇒d^{'}=\sqrt{10} .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct


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