2.935 is in between those 2
Answer: 8 hours.
Step-by-step explanation:
We have the relation:
Time = distance/velocity
Distance = 50 miles
Velocity in horse = 9mph
Velocity walking = 3 1/2 mph = 3.5 mph
Then, if T is the total time, X is the distance that he travels in horse and Y is the distance that he travels by foot, we have:
X + Y = 50 miles:
T/2 = X/9mph
T/2 = Y/3.5mph
Then we have:
X/9mph = Y/3.5mph
X = Y*(9/3.5)
And by the first relation:
X = 50 mi - Y
then we have:
50mi - Y = Y*(9/3.5)
50mi = Y + Y*(9/3.5) = Y*(1 + 9/3.5) = Y*3.57
Y = 50mi/3.57 = 14mi
Then we have:
T/2 = 14mi/3.5mph
T = 2*(14/3.5) hours = 8 hours
B hope this helped have a nice day! =D
Oh yes 4x5 is another answer so yep god I forgot that sorry!
Somewhere you're given the equation for height as a function of time:
... h(t) = -16t² + v₀·t . . . . . . where v₀ is the initial vertical velocity in ft/s
For v₀ = 224, this becomes
... h(t) = -16t² + 224t
And this can be rewritten in vertex form as
... h(t) = -16(t² + 14t)
... h(t) = -16(t² + 14t +7²) +16·7² . . . . . complete the square (add the square of half the t coefficient inside parentheses; add the opposite of that amount outside parentheses)
... h(t) = -16(t +7)² + 784
The vertex of this downward-opening parabola is (7, 784), so ...
The rocket reaches its maximum height at 7 seconds.
The maximum height of the rocket is 784 feet.
Although I don't see 1950, 1988, or 2010 on your model, I did calculate the average for 1972, 1982, 1992, and 2002: the average that I got was 1.6025 (this answer has not been rounded due to the fact that I don't know if you need to round it)
hope this helps