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2 years ago

Find the distance between the points (6,-4) and (-3,-4) .

Mathematics

1 answer:

umka2103 [35]2 years ago

3 0

The right answer is 9 units.

please see the attached picture for full solution

Hope it helps

Good luck on your assignment:)

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there are 40 black balls this is 4 more than twice the number of yellow balls how many yellow boll are there

miss Akunina [59]

Answer:

There are 5 yellow balls

Step-by-step explanation:

40/4 = 10

10/2 = 5

8 0

3 years ago

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1 2 3 4 5 6 7 8 9 10 TIME REMAINING 54:32 Because the lid of a marker is wider than the marker itself, a set of markers can be p

tia_tia [17]

Answer:

10 Square Inches

Step-by-step explanation:

Trapezoid

Base =12 inches

Height =10 inches

Top side= 10 inches.

Area of a Trapezoid $=\frac{1}{2}(a+b)h, $where a and b are the lengths of the base and top respectively$$

$=\frac{1}{2}(10+12)*10\\=5*22=110 \:Square\:Inches$

Area of the Trapezoid=110 Square Inches

Rectangle

Base = 12 inches

Height =10 inches.

Area of a Rectangle=Base X Height

=12 X 10

=120 Square Inches

Difference in Area between the two packages

Difference=Area of Rectangle-Area of Trapezoid

=120-110

=10 Square Inches

5 0

3 years ago

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If sinA+cosecA=3 find the value of sin2A+cosec2A

Irina18 [472]

Answer:

$\sin 2A + \csc 2A = 2.122$

Step-by-step explanation:

Let $f(A) = \sin A + \csc A$ , we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

$\csc A = \frac{1}{\sin A}$ (1)

$\sin^{2}A +\cos^{2}A = 1$ (2)

Now we perform the operations: $f(A) = 3$

$\sin A + \csc A = 3$

$\sin A + \frac{1}{\sin A} = 3$

$\sin ^{2}A + 1 = 3\cdot \sin A$

$\sin^{2}A -3\cdot \sin A +1 = 0$ (3)

By the quadratic formula, we find the following solutions:

$\sin A_{1} \approx 2.618$ and $\sin A_{2} \approx 0.382$

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

$\sin A \approx 0.382$

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

$A \approx 22.457^{\circ}$

Then, the values of the cosine associated with that angle is:

$\cos A \approx 0.924$

Now, we have that $f(A) = \sin 2A +\csc2A$ , we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used: