9/3 or 3
slope is rise over run. or x over y.
look at your Y points... 1, 10, 19, 28, 37. They go up 9 each time, right? 1 + 9 = 10 + 9 = 19...etc.
Now, look at your X points... 0, 3, 6, 9, 12. They go up 3 each time, right? 0 + 3 = 3 + 3 = 6...etc.
Since you go up 9 for the y axis and 3 for the x axis...
9/3
Positive correlation the more years of education the more you'll earn
Answer:
-0.4
Step-by-step explanation:
Since x=4 is not a critical point, you can simply evaluate the function. You can do this in your head.
(2√4 -6)/(9 -4) = (2·2 -6)/5 = -2/5 = -0.4
Simplifying
34 = 10 + 4q
Solving
34 = 10 + 4q
Solving for variable 'q'.
Move all terms containing q to the left, all other terms to the right.
Add '-4q' to each side of the equation.
34 + -4q = 10 + 4q + -4q
Combine like terms: 4q + -4q = 0
34 + -4q = 10 + 0
34 + -4q = 10
Add '-34' to each side of the equation.
34 + -34 + -4q = 10 + -34
Combine like terms: 34 + -34 = 0
0 + -4q = 10 + -34
-4q = 10 + -34
Combine like terms: 10 + -34 = -24
-4q = -24
Divide each side by '-4'.
q = 6
Simplifying
q = 6
hope this helps please mark brainliest
Answer: (b) The focus of an ellipse is always located precisely at the center of the ellipse.
Step-by-step explanation:
An ellipse is defined as <em>"a closed curve with two axes of symmetry (major axis and minor axis) that results in cutting the surface of a cone by an oblique plane to the axis of symmetry with an angle greater than that of the generatrix with respect to the axis of revolution"</em>. That is why the ellipse is considered a conic figure.
To understand it better: an ellipse has two points on its major axis that are equidistant from the center , which are called foci, being this distance constant. In addition, the eccentricity allows to know how far the foci are from the center of the ellipse.
Therefore, the statement that indicates an ellipse has only one focus located precisely at the center is incorrect.
