3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPP

1 answer:

7 0

For question 22, divide each number by 1.41 to see which one produces a quotient larger than 0.9. d is the answer.
For #23, multiple 0.155 million by 86%, the result is 133,300
again, d is the correct answer.

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Julian saved between $ 30 and $ 52 over the summer. His friend Daniela saved twice as much. Let n represent the amount of money

maks197457 [2]

Y = (30 + 52) * 2

Y = (82) * 2

Y = 164

Daniela saved $164

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4 years ago

Rhonda Hartman purchased a camper for 4,927.00, a lantern for 32.87, and a propane grill for 86.50. the state tax is 4.5 percent

Butoxors [25]

The total amount of tax on her purchases is $378.47

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4 years ago

Jennifer and carmen have the same amount of money to spend on carnival tickets Jennifer buys 4 tickets and has 8.40 left carmen

Sliva [168]

Do the following:

$8.40-$7.15=$1.25
Then divide 1.25 by the difference of tickets which is 3
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3 years ago

A polymer is manufactured in a batch chemical process. Viscosity measurements show that it is approximately normally distributed

PilotLPTM [1.2K]

Answer: (751.05, 766.95)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :-

$\overline{x}\pm z*\dfrac{\sigma}{\sqrt{n}}$ ,

where $\sigma$ =population standard deviation.

$\overline{x}$ = sample mean

n= sample size

z* = Two-tailed critical z-value.

Given : $\sigma= 20$

n= 42

$\overline{x}=759$

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576

Now, the 99% confidence interval around the true population mean viscosity :-

$759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)$

∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)

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3 years ago

A lemonade recipe calls for LaTeX: \frac{1}{4}1 4 cup of lemon juice for every cup of water.

Delvig [45]

Can you explain more

pls

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3 years ago