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Anastaziya [24]
3 years ago
6

Answers? domain and range of graphs

Mathematics
1 answer:
Andru [333]3 years ago
4 0

Answer:

1. domain [2,3) range (1,3]

2. domain (-4, 3] range (-2,3]

3. domain [-5,4] range [0, 4]

4. domain [-3,1] range [-2,2]

5. domain (-4,0) range (0,4)

6. domain [-4,4] range [-4,4]

7. domain [-1,3) range (-4,4)

8. domain (-5,5] range [-2,2)

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Lin can read at rate of 20 pages in 35 minutes she just borrowed a book from library that 48 pages how many minutes will it take
tiny-mole [99]

Answer:

84

Step-by-step explanation:

4 0
3 years ago
For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
ICE Princess25 [194]

Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

so

A1=\frac{1}{2}*6*6=18\ cm^{2}

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

r=6/2=3\ cm

substitute

A2=\pi (3)^{2}/2

A2=(9/2) \pi\ cm^{2}

The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

the circumference of a semicircle is equal to

C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

5 0
3 years ago
Translate each inequality. ¨a minimum of 10¨
Alexandra [31]

Answer:

X ≥ 10

Step-by-step explanation:

5 0
2 years ago
50 points for the person to answer these :)
svetoff [14.1K]

I'm assuming you don't still need these? Sorry I didn't see this in time

7 0
3 years ago
Distance between (-15 , 18 and ( 20 ,18)
Kipish [7]

From the Formula:

Distance = Sqr Root [ (x2- x1)^2 + (y2 - y1)^2 ]

Distance = Sqr Root [ (20 --15)^2 + 18 -18)^2 ]

Distance = Sqr Root [ 1,225 + 0]

Distance = 35


8 0
3 years ago
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