All categories

3 years ago

Answers? domain and range of graphs

Mathematics

1 answer:

Andru [333]3 years ago

4 0

Answer:

1. domain [2,3) range (1,3]

2. domain (-4, 3] range (-2,3]

3. domain [-5,4] range [0, 4]

4. domain [-3,1] range [-2,2]

5. domain (-4,0) range (0,4)

6. domain [-4,4] range [-4,4]

7. domain [-1,3) range (-4,4)

8. domain (-5,5] range [-2,2)

You might be interested in

Lin can read at rate of 20 pages in 35 minutes she just borrowed a book from library that 48 pages how many minutes will it take

tiny-mole [99]

Answer:

Step-by-step explanation:

4 0

3 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

5 0

3 years ago

Translate each inequality. ¨a minimum of 10¨

Alexandra [31]

Answer:

X ≥ 10

Step-by-step explanation:

5 0

2 years ago

50 points for the person to answer these :)

svetoff [14.1K]

I'm assuming you don't still need these? Sorry I didn't see this in time

7 0

3 years ago

Distance between (-15 , 18 and ( 20 ,18)

Kipish [7]

From the Formula:

Distance = Sqr Root [ (x2- x1)^2 + (y2 - y1)^2 ]

Distance = Sqr Root [ (20 --15)^2 + 18 -18)^2 ]

Distance = Sqr Root [ 1,225 + 0]

Distance = 35

8 0

3 years ago