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Mekhanik [1.2K]
3 years ago
5

Write a equation for the line parallel to

Mathematics
1 answer:
Llana [10]3 years ago
8 0
Paralell has same slope
y=mx+b
m=slope
b=yint

same slope so other equation is
y=4x+b

input given point
(2,0)
x=2
y=0
0=4(2)+b
0=8+b
minus 8 both sides
-8=b

the equation is y=4x-8
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GREYUIT [131]

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4 0
3 years ago
Read 2 more answers
Can someone please help with #16
ollegr [7]

Answer:

∠ WZX = 50°

XW is not an altitude.

Step-by-step explanation:

16. See the attached figure.

XW is the angle bisector of ∠ YXZ, hence, ∠ WXY = ∠ WXZ

Now, given that ∠ YXZ = 8x + 34 and ∠ WXY = 10x - 13

Hence, ∠ YXZ = 2 ∠ WXY

⇒ 8x + 34 = 2(10x - 13)

⇒ 8x + 34 = 20x - 26

⇒ 12x = 60

⇒ x = 5.

Hence, ∠ XZY = ∠ WZX = 10x = 50° (Answer)

Now, ∠ WXZ = ∠ WXY = 10x - 13 = 37°

Hence, from Δ WXZ,

∠ WZX + ∠ WXZ + ∠ XWZ = 180°

⇒ 50° + 37° + ∠ XWZ = 180°

⇒ ∠ XWZ = 93° ≠ 90°

Hence, XW is not an altitude. (Answer)

6 0
3 years ago
Help pleaseeee!!!!!!!
mylen [45]
Help with what? I need more information
6 0
3 years ago
Easy points. this is due tomorrow, the formula is given but im not sure how to solve. help? x
ozzi

\sf{\qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

  • h = height of cone = 10 cm

  • r = radius of cone/sphere = ??

  • Volume of cone = 270 pi cm³

Volume of cone is :

\qquad \sf  \dashrightarrow \:v = 270 \pi

\qquad \sf  \dashrightarrow \: \dfrac{1}{3}   \cancel\pi {r}^{2} h = 270 \cancel\pi

\qquad \sf  \dashrightarrow \:r {}^{2}  \sdot10 = 270 \times 3

\qquad \sf  \dashrightarrow \: {r}^{2}  = 810 \div 10

\qquad \sf  \dashrightarrow \: { {r}^{2} }^{}  = 81

\qquad \sf  \dashrightarrow \:r =  \sqrt{81}

\qquad \sf  \dashrightarrow \:r = 9 \:  \: cm

Now, let's calculate volume of solid sphere with same radius is ~

\qquad \sf  \dashrightarrow \:vol =  \dfrac{4}{3}  \pi {r}^{3}

\qquad \sf  \dashrightarrow \:vol =  \dfrac{4} {3}   \sdot\pi \sdot  {9}^{3}

\qquad \sf  \dashrightarrow \:vol =  \dfrac{4} {3}   \sdot\pi \sdot  729

\qquad \sf  \dashrightarrow \:vol =  {4} {}    \sdot243 \sdot\pi

\qquad \sf  \dashrightarrow \:vol =  97 2\pi  \:  \:  {cm}^{3}

So, volume of the solid sphere in terms of pi is :

  • 972 pi cm³

<u>note</u> : the solid figure attached below the cone is a hemisphere, so if the volume of hemisphere is asked then just dovide the result for sphere by 2. that is :

  • 972pi / 2 = 486 pi cm³
4 0
2 years ago
PLEASE HELP!! Make sure to give exact coordinates.
Nikolay [14]
(1,5) (2,10) (3,15) (4,20) (5,25) (6,30) (7,35) (8,40) until she sells out. 
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4 years ago
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