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Mrac [35]
3 years ago
7

How to draw a locus of point D

Mathematics
1 answer:
allsm [11]3 years ago
4 0
 To draw a locus point you have to draw<span> the half way line through the two </span>points. You can do this by drawing<span> the line bisector through AB points. Just open your compass to ¾ of the distance AB and then </span>draw<span> two arcs from both sides of your line. Once this is done </span>draw the line passing through the two intersection points<span>.

Hope this helps :)</span>
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How can you use unit rates in multiplication to solve for missing measures and equivalent ratio problems?
vodka [1.7K]
By viewing equivalent ratios and rates as deriving from, and extending, pairs of rows (or columns) in the multiplication table and by analyzing simple drawings that indicate the relative size of quantities.
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3 years ago
PLEASE HELP. !!!!!!!!!
Elan Coil [88]
That question is already answered on brainly. Search it up
4 0
3 years ago
In a number with at least two digits, the last number was removed. The resulting number was n smaller than ghe previous one.
BartSMP [9]

Answer:

The largest possible value of n is 11.

(A) is correct option.

Step-by-step explanation:

Given that,

The number with at least two digits,the last number was removed. The resulting number was n smaller than the previous one.

We need to find the largest possible value of n

Using given data,

The smallest number of two digit is 10.

Now, we removed last digit then we get 1 which is equal to 10 divided 10.

So, n = 10

But the largest number of two digit is 99.

We removed last digit then we get 9 which is equal to 99 divided 11.

So, n = 11

Hence, The largest possible value of n is 11.

(A) is correct option.

5 0
3 years ago
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expeople1 [14]
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6 0
2 years ago
Read 2 more answers
In triangle PQR, PR = 23mm, QR = 39mm, and m&lt;R = 163 degrees. Find the area of the triangle to the nearest tenth.
Schach [20]

Answer: 131.1287 square mm (approx)

Step-by-step explanation:

The area of a triangle,

A=\frac{1}{2} \times s_1\times s_2\times sin \theta

Where s_1 and s_2 are adjacent sides and \theta is the include angle of these sides,

Here PR and QR are adjacent sides and ∠R is the included angle of these sides,

Thus, we can write,

s_1 = PR= 23\text{ mm}, s_2=QR=39\text{ mm} and \theta = 163^{\circ},

Thus, the area of the triangle PQR,

A=\frac{1}{2} \times 23\times 39\times sin163^{\circ}

A=\frac{262.257419136}{2} = 131.128709568\approx 131.1287\text{ square mm}

5 0
3 years ago
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